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SQLServer2005 XML在T-SQL查询中的典型应用,该怎么处理

热度:100   发布时间:2016-04-27 19:11:36.0
SQLServer2005 XML在T-SQL查询中的典型应用
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/*SQLServer2005 XML在T-SQL查询中的典型应用整理:fcuandy时间:2008.11.7前言:    此文只讲xml数据类型及相应的一些操作方法在解决日常T-SQL编程中的一些应用,而避开xml modify,xml schema,xml索引,命名空间等这些语法性或者生硬的一些问题(这些语法您可以查联机丛书),即此文主要讲以xml的一些操作特性及xquery去解决编程问题.Tags:    xquery ,FLWOR迭带 ,sql:column ,sql:variable ,nodes ,value ,query ,xpath ,xquery function, if, 聚合函数, xs:function等典型应用举例:*/--(1)--====================================================================--拆分DECLARE @s VARCHAR(100)SET @s='a,b,c,dd,ee,f,aa,a,aa,f'--常规做法(sql2000常用),以一split函数拆分串为表类型结构,如--SELECT * FROM dbo.split(@s,',') a--当然,也可能是循环去拆分,或者以一输助表的identity列利用charindex等函数拿identity列值与','的位置匹配实现拆分--这些做法,roy_88及本人以前都整理过,不再累赘,可见推荐贴。即便 是xml法,也贴过多次,下面一笔带过--XML做法:SELECT b.v FROM    (SELECT CAST('<r>' + REPLACE(@s,',','</r><r>') + '</r>' AS XML) x) a   --将字串","换换为"</r><r>"并前后拼上<r>,</r>以用来构造xml串CROSS APPLY    (SELECT v=t.x.value('.','VARCHAR(10)') FROM a.x.nodes('//r') AS t(x) ) b  --使用 xml.nodes函数将xml串拆分为行/*abcddeefaaaaaf*/--(2)--====================================================================--去重,@s中出现的元素,重复的只要一个,希望结果为 'a,b,c,dd,ee,f'--常规做法,循环或函数,或临时表拆后distinct--XML做法:--a.在(1)的基础上进行;WITH fc AS   --定义cte命名,[email protected](    SELECT DISTINCT b.v v            FROM                (SELECT CAST('<r>' + REPLACE(@s,',','</r><r>') + '</r>' AS XML) x) a            CROSS APPLY                (SELECT v=t.x.value('.','VARCHAR(10)') FROM a.x.nodes('//r') AS t(x) ) b)--对这个表利用xml方法进行行值拼接SELECT STUFF(b.v.value('/r[1]','varchar(100)'),1,1,'')    FROM    (SELECT v=(SELECT ',' + v FROM fc FOR XML PATH(''),ROOT('r'),TYPE)) b/*a,aa,b,c,dd,ee,f*/--b FLWOR语句 + T-SQL组合:SELECT STUFF(v,1,1,'') FROM    (SELECT CAST('<r>' + REPLACE(@s,',','</r><r>') + '</r>' AS XML) x) aCROSS APPLY    (SELECT x=(SELECT t.x.value('.','varchar(10)') v,idx=ROW_NUMBER() OVER(ORDER BY GETDATE()) FROM a.x.nodes('//r') AS t(x) FOR XML PATH('r'),TYPE)) b --利用row_number得到唯一idxCROSS APPLY    (SELECT v=CAST(b.x.query('for $r in //r where count(//r[v=$r/v and idx<$r/idx])=0 return concat(",",xs:string($r/v[1]))') AS VARCHAR(MAX))) c  --类似count计数法,取得v相同的节点集idx值最小的节点,原型为:--SELECT * FROM tb a WHERE 1>(SELECT COUNT(*) FROM tb WHERE v=a.v AND id<a.id)/*a ,b ,c ,dd ,ee ,aa ,f*/--c distinct-valuesSELECT REPLACE(v,' ',',') FROM    (SELECT CAST('<r>' + REPLACE(@s,',','</r><r>') + '</r>' AS XML) x) aCROSS APPLY    (SELECT CAST(a.x.query('distinct-values(//r)') AS VARCHAR(MAX)) v) b  --直接调用distinct-values函数来操作/*a,b,c,dd,ee,f,aa*/-- 导入去重, last() , position()DECLARE   @doc  xmlSET   @doc   ='<?xml version="1.0" encoding="gb2312" ?><employees>    <employee>        <empid>e0001</empid>        <name>萧峰</name>    </employee>    <employee>        <empid>e0002</empid>        <name>段誉</name>    </employee>    <employee>        <empid>e0003</empid>        <name>王语嫣</name>    </employee>    <employee>        <empid>e0003</empid>        <name>张无忌</name>    </employee></employees>'create table people2 (     personid varchar(10)  primary key ,    name varchar(20)  )INSERT people2SELECT DISTINCT b.* FROM    (SELECT x = @doc.query('for $e in //employee  return  //employee[empid = $e/empid][last()]')) a  --FLWOR时,用当前节点去//emploee节点集中找节点集中empid等于当前节点的empid, 在找到的集合中取最后一个利用last()函数CROSS APPLY    (SELECT id=t.x.value('empid[1]','varchar(100)'),name=t.x.value('name[1]','varchar(100)') FROM a.x.nodes('//employee') AS t(x)) bSELECT * FROM people2/*e0001    萧峰e0002    段誉e0003    张无忌*/GOdrop table people2 GO--同组一选多,也可应用此方法,不过没有必要,就不再累赘了。--(3)--====================================================================--列名,列值相关--a,按行聚合declare @t table(Sname nvarchar(5),  V1 float,    V2 float,    V3 float,      V4 float,    V5 float,      V6 float) insert @t select N'张三',    0.11 , 0.21 , 0.29,  0.32 ,   0.11,    0.08 insert @t select N'李四',    0.01 , 0.61 , 0.21,  0.73 ,   0.21,    0.12 insert @t select N'张五',    0.31 , 0.21 , 0.23,  0.33 ,   0.91,    0.65 insert @t select N'张六',    0.59 , 0.11,  0.26,  0.13,    0.01,    0.15 select b.* from    (select x=cast((select * from @t for xml path('r')) as xml)) across apply    (        select name=x.query('./Sname/text()'),v=x.query('max(./*[local-name(.)!="Sname"])') from a.x.nodes('//r') as t(x)          --r为二级节点(因为文档本身无根节点,即为每项的顶级节点)即为一个r节点表示一条记录. r下级节点,每个表示一个列,因为列名未知,所以用/*匹配所有节点,因为name为区别列,不参与聚合运算,故用local-name取得来过滤    ) b/*张三    0.32李四    0.73张五    0.91张六    0.59*/--b ,由值引到取列if not object_id('T1') is null    drop table T1GOCreate table T1([tId] int,[tName] nvarchar(4))Insert T1select 1,N'zhao' union allselect 2,N'qian' union allselect 3,N'sun'Go--> --> 借且(Roy)生成測試數據 if not object_id('T2') is null    drop table T2GoCreate table T2([tId] int,[zhao] nvarchar(1),[qian] nvarchar(1),[sun] nvarchar(1))Insert T2select 1,N'a',N'b',N'c' union allselect 2,N'd',N'e',N'f' union allselect 3,N'g',N'h',N'i'GoSELECT c.tid,c.tName,v FROM t1 cCROSS APPLY    (SELECT x=(SELECT * FROM t2 WHERE tid=c.tid FOR XML PATH('r'),TYPE)) aCROSS APPLY    (SELECT v=t.x.query('./*[local-name(.)=xs:string(sql:column("c.tName")) ]/text()')         FROM a.x.nodes('//r') AS t(x)    ) b/*1    zhao    a2    qian    e3    sun    i*/--c, 列名,列值,与系统表 CREATE TABLE tb(f1 INT,f2 INT,x INT,z INT,d INT,ex INT,dd INT,vv INT) INSERT tb SELECT 1,2,3,5,11,3,2423,33 GO SELECT * FROM tb GO SELECT name,v FROM  ( SELECT name FROM sys.columns WHERE object_id=object_id('tb','u') ) a CROSS JOIN  (SELECT x=(SELECT * FROM tb FOR XML PATH('r'),TYPE)) b CROSS APPLY (SELECT v=t.x.query('./*[local-name(.)=xs:string(sql:column("a.name")) ]/text()') FROM b.x.nodes('//r') AS t(x) ) c /*f1    1f2    2x    3z    5d    11ex    3dd    2423vv    33*/GO DROP TABLE tbGO--(4)--一些综合计算--以下表 ta.a值 yyyymmdd-yyyymmdd表连续时间段,","表单个日期If object_id('ta','u') is not null     Drop table taGoCreate table ta(a varchar(100))GoInsert into taselect '1 ¦ ¦20080101-20080911' union allselect '2 ¦ ¦20080101,20080201,20080301,20080515,20080808'union allselect '3 ¦ ¦20080101,20080201,20080301,20080515,20081108'Godeclare @s varchar(8)select @s= convert(varchar(8),getdate(),112)select stuff(replace(replace(cast(x as varchar(1000)),'</item><item>',case when type='1' then '-' else ',' end),'</item>',''),1,6,type + ' ¦ ¦') a    from    (        select left(a,1) type,             cast(                    '<item>'                     +                     replace(                        stuff(a,1,5,''),                        case when left(a,1)=1 then '-' else ',' end,                        '</item><item>'                        )                    +                     '</item>'                AS XML                ) x        from ta    ) base    where x.value('            if (sql:column("base.type")="1") then                if(                    (/item/text())[1]<sql:variable("@s")                    and                    (/item/text())[2]>sql:variable("@s")                )                then 1                else 0            else                count(//item[text()>sql:variable("@s")])            '            ,            'int'            )>0go待续。。
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