比如时间跨度为2002-2012
查询结果为
2002
2003
2004
2005
2006
2007
2008
2009
2010
2011
2012
------解决方案--------------------
- SQL code
--sql 2005declare @startDate datetimedeclare @endDate datetimeSELECT @startDate = '2002-01-01' ,@endDate = '2012-01-01';WITH tb AS (SELECT @startDate AS 'date'UNION ALLSELECT DATEADD(yy,1,date) FROM tb WHERE datepart(yy,DATE)<datepart(yy,@endDate))SELECT datepart(yy,tb.date) from tb/*-----------20022003200420052006200720082009201020112012(11 行受影响)*/