- SQL code
表1 添加新闻的表id mid start_time name1 1 03 30 2012 4:00AM A 2 1 03 30 2012 5:00AM A3 1 03 30 2012 6:37AM A4 2 03 31 2012 4:00AM B5 2 03 31 2012 5:00AM B6 2 03 31 2012 6:00AM B 表2 新闻名称表 mid name 1 A 2 B表3 已删除新闻的表id mid start_time end_time name1 1 03 30 2012 7:00AM 03 30 2012 12:00AM A 2 1 03 30 2012 8:00AM 03 30 2012 12:00AM A3 1 03 30 2012 9:37AM 03 30 2012 12:00AM A4 2 03 31 2012 7:00AM 03 31 2012 12:00AM B5 2 03 31 2012 8:00AM 03 31 2012 12:00AM B6 2 03 31 2012 9:00AM 03 31 2012 12:00AM B
表结构如上
- SQL code
问题1:如何查询每天新添加的新闻名称以及新闻数量想得到结果是mid name (数量) 1 A 6 2 B 6在3月30号添加新闻名为A的新闻6条,新闻名为B的新闻6条语句1:select mid,COUNT(id) from 表1 where DATEDIFF(DAY,convert(varchar(10),start_time ,120),GETDATE())=20 group by (id);结果mid (数量)1 3只能查询出 当天添加的新闻和数量 而当天已经删除了的新闻和新闻名没法查询出来请大家帮助下问题2 查询出每天删除的新闻名称,以及新闻数量想得到结果是mid name (数量) 1 A 3 2 B 3语句2:select mid,count(id) form 表3 where DATEDIFF(DAY,convert(varchar(10),start_time ,120),GETDATE())=20 group by (id);结果mid (数量)1 32 3
请求教下 这样的语句该怎么写 还有就是 根据时间查询数据的语句是否有问题
------解决方案--------------------
看看满足你要求不?
- SQL code
IF OBJECT_ID('NewsAdd') IS NOT NULL DROP TABLE NewsAdd;IF OBJECT_ID('NewsDel') IS NOT NULL DROP TABLE NewsDel;IF OBJECT_ID('NewsItems') IS NOT NULL DROP TABLE NewsItems;GOCREATE TABLE NewsAdd(id int, mid int, start_time datetime , Tname nvarchar(16), Iname nvarchar(16), Tid int, Iid int);CREATE TABLE NewsDel(id int, mid int, start_time datetime, end_time datetime , Tname nvarchar(16), Iname nvarchar(16), Tid int, Iid int);CREATE TABLE NewsItems( tid int, Tname nvarchar(16));GOINSERT INTO NewsAdd(id, mid, start_time, Tname, Iname, Tid, Iid)select 1, 1, '03 30 2012 6:00AM', '时事新闻', '地铁出轨', 1, 1 union allselect 2, 2, '03 30 2012 7:00AM', '时事新闻', '火车出轨', 1, 2 union allselect 3, 5, '03 31 2012 6:00AM', '军事新闻', '朝鲜发射火箭', 2, 5 union allselect 4, 6, '03 31 2012 7:00AM', '军事新闻', '朝鲜火箭发射失败', 2, 6;INSERT INTO NewsDel(id, mid, start_time, end_time, Tname, Iname, Iid, Tid)select 1, 3, '03 30 2012 8:00AM', '03 30 2012 12:00AM', '时事新闻', '汽车相撞', 3, 1 union allselect 2, 4, '03 30 2012 9:00AM', '03 30 2012 12:00AM', '时事新闻', '自行车相撞', 4, 1 union allselect 3, 7, '03 30 2012 8:00AM', '03 31 2012 12:00AM', '军事新闻', '美伊问题 ', 7, 2 union allselect 4, 8, '03 31 2012 9:00AM', '03 31 2012 12:00AM', '军事新闻', '叙利亚问题', 8, 2;INSERT INTO NewsItems(tid, Tname)select 1, '时事新闻' union allselect 2, '军事新闻';--select * from NewsAdd;--select * from NewsDel;--select * from NewsItems;select n.Tname, b.Numfrom ( select tid, COUNT(1) as Num from ( select tid, start_time from NewsAdd union all select tid, start_time from NewsDel ) a where start_time between '2012-03-30' and '2012-03-31 23:59' -- 这个条件语句你可以按下面改,因为这里没有数据,按下面改就没有结果了, -- 所以暂时按上面的临时写法 --where start_time >= DATEADD(DD, -1, convert(varchar(10), GETDATE(), 120)) -- and start_time < convert(varchar(10), GETDATE(), 120) group by tid ) bjoin NewsItems n on b.tid = n.tidselect n.Tname, b.Numfrom ( select tid, count(1) as Num from NewsDel where start_time between '2012-03-30' and '2012-03-31 23:59' -- 这里按上面一样改就好了 group by tid ) bjoin NewsItems n on b.tid = n.tid/*Tname Num---------------- -----------时事新闻 4军事新闻 4Tname Num---------------- -----------时事新闻 2军事新闻 2*/