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SQL中declare用法解决方案

热度:5   发布时间:2016-04-27 11:12:28.0
SQL中declare用法
C# code
            var strSQL = new StringBuilder();            strSQL.Append("declare @rodno varchar(50) ");            strSQL.Append("set @rodno = @GetRod ");            strSQL.Append("SELECT 'aaa'  AS Type,a.rodNO as RodNO,a.starttime  AS Starttime,b.endtime  AS Endtime ");            strSQL.Append("FROM PRO_COREVAD_BEGIN a,PRO_COREVAD_END b ");            strSQL.Append("WHERE [email protected] ");            strSQL.Append("AND a.rodNO=b.rodNO ");            strSQL.Append("union ");            strSQL.Append("SELECT 'bbb'  AS Type,a.rodNO,a.starttime,b.endtime ");            strSQL.Append("FROM PRO_Coresinter_BEGIN a,PRO_Coresinter_END b ");            strSQL.Append("WHERE a.rodNO LIKE (@rodno+'%') ");            strSQL.Append("AND a.rodNO=b.rodNO ");            strSQL.Append("union ");            strSQL.Append("SELECT 'ccc'  AS Type,c.rodNo,a.starttime,b.endtime ");            strSQL.Append("FROM PRO_CoreVacuumdegass_BEGIN a,PRO_CoreVacuumdegass_END b,PRO_CoreVacuumdegass_BatchInfo c ");            strSQL.Append("WHERE c.rodNO LIKE (@rodno+'%') ");            strSQL.Append("AND a.batchid=b.batchid AND a.batchid=c.batchid AND c.batchid = (SELECT MAX(batchid) ");            strSQL.Append("FROM PRO_CoreVacuumdegass_BatchInfo ");            strSQL.Append("WHERE rodNo LIKE (@rodno+'%')) --ddd"); SqlParameter[] parameters = {                                            new SqlParameter("@GetRod", SqlDbType.VarChar,50)                                        };            parameters[0].Value = rodno;            var ds = SQLHelper.GetDs(strSQL.ToString(), parameters);
[email protected]@rodno赋值,但是返回的数据库只有一行数据,求解释

------解决方案--------------------
@GetRod 是程序的参数?
delphi的sql参数好像是 :参数名
这样拼凑应该可以吧:
strSQL.Append("set @rodno = "+rodno+" ");

------解决方案--------------------
如果都是sql的变量
则必须decalre过的
看你的需求,[email protected]
拼凑一下就行了,[email protected]
------解决方案--------------------
你这写法你自己看着难受不?
为什么不在数据写好存储过程然后用程序传参调用呢!
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