SQL 在学生中查询出第5名至第10名的学生(只要第五名到第十名这个区间的数据)
按照Score_sum的从高到低排序。
求详细代码。谢谢!
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看你的截图,应该是2005或者以上版本,可以用下面代码,对最外层的*号处理一下就可以了。比如把oid在最外层不显示,或者选择你需要的列
SELECT *
FROM ( SELECT * ,
ROW_NUMBER() OVER ( ORDER BY score_suDESCsc ) oid
FROM TB
) a
WHERE oid BETWEEN 5 AND 10
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select * from a where Score_sum
not in (select top 4 Score_sum from a order by Score_sum desc)
order by Score_sum desc
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取n到m行
1.
select top (n-m+1) * from tablename where id not in (select top n id from tablename order by id asc/*
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desc*/)
2.
select top m * into 临时表(或表变量) from tablename order by columnname -- 将top m笔插入到临时表
set rowcount n --只取n条结果
select * from 表变量 order by columnname desc
3.
select top n * from
(select top m * from tablename order by columnname) a
order by columnname desc
4.如果tablename里没有其他identity列,那么:
先生成一个序列,存储在一临时表中.
select identity(int) id0,* into #temp from tablename
取n到m条的语句为:
select * from #temp where id0 > =n and id0 <= m
如果你在执行select identity(int) id0,* into #temp from tablename这条语句的时候报错,那是因为你的DB中间的select into/bulkcopy属性没有打开要先执行:
exec sp_dboption 你的DB名字,'select into/bulkcopy',true
5.如果表里有identity属性,那么简单:
select * from tablename where identity_col between n and m
6.SQL2005开始.可以使用row_number() over()生成行号
;with cte as
(
select id0=row_number() over(order by id),* from tablename
)
select * from cte where id0 between n to m
方法太多了啊
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if OBJECT_ID('tt') is not null drop table tt
create table tt(Std_id int,Score_Date datetime,Chinese float,Math float,Score_sum float)
insert into tt values (1,GETDATE(),1,2,3)
insert into tt values (2,GETDATE(),2,3,5)
insert into tt values (3,GETDATE(),3,4,7)
insert into tt values (4,GETDATE(),4,5,9)