在Python中为字符串输出分配随机生成的整数_python

我正在使用一个随机事实生成器，该生成器采用一个随机生成的数字（在本例中为1 -10）并将该数字分配给一个告诉用户随机事实的字符串输出。

到目前为止，这是我能够将所有代码组合在一起的全部内容：

#Greeting
a = "Hello, who am I speaking to?"
print("Welcome, " + input(a) + "!" + " Lets see what fact you rolled...")

#Random Number Generator
import random
for x in range (1):
    randomNumber = random.randint(1, 10)
    print(randomNumber)

#Loop function   
def check_val(randomNumber, title, answer):
        while True:
            if input(randomNumber) == title:
                print(answer)
                break
            else:
                print("I dont know.")

#Facts
def fact():

            randomNumber, answer = {}, {}
            randomNumber[1] = ([1])
            answer[1] = "Fact1"
            randomNumber[2] = ([2])
            answer[2] = "Fact2"
            randomNumber[3] = ([3])
            answer[3] = "Fact3"
            randomNumber[4] = ([4])
            answer[4] = "Fact4"
            randomNumber[5] = ([5])
            answer[5] = "Fact5"
            for k in randomNumber:
                check_val(randomNumber[k], k, answer[k])


fact()

运行此代码时，我得到以下输出：

你好，我在跟谁说话？j欢迎，j！ 让我们看看您滚动了什么事实... 5 [1]

我无法获取该随机整数（5）并将其分配给随机事实＃5。

关于如何将这些随机整数分配给可用输出的任何想法？

嗨，芽，您在这里进行了很多工作，您可以使用list存储事实来简化此过程，这是可以构建的更好格式。 如@JonClements所述，我们可以使用random.randrange(len(facts))如果我们想更改列表中的事实数量，这将使我们的代码更具适应性。

import random

while True:
    name = input("\nHello, Who am I speaking to?\n")
    print(f"\nWelcome, {name}! Lets see what you rolled..."

    facts = [ 
        'Fact one',
        'Fact two',
        'Fact three',
        'Fact four',
        'Fact five',
        'Fact six',
        'Fact seven',
        'Fact eight',
        'Fact nine',
        'Fact ten'
    ]   

    selection = random.randrange(len(facts))

    print(facts[selection])

#Greeting
a = "Hello, who am I speaking to?"
print("Welcome, " + input(a) + "!" + " Lets see what fact you rolled...")

#Random Number Generator
import random
for x in range (1):
    randomNumber = random.randint(1, 10)
    print(randomNumber)   <--- your printing 5

#Loop function   
def check_val(randomNumber, title, answer):
        while True:
            if input(randomNumber) == title: <--- answer argument which were passed was [1] remember so it asks you to write something with the text [1]
                print(answer)
                break
            else:
                print("I dont know.")

#Facts
def fact():

            randomNumber, answer = {}, {}   <--- your 5 nol longer exist because you now overwrote it with a dict
            randomNumber[1] = ([1])
            answer[1] = "Fact1"
            randomNumber[2] = ([2])
            answer[2] = "Fact2"
            randomNumber[3] = ([3])
            answer[3] = "Fact3"
            randomNumber[4] = ([4])
            answer[4] = "Fact4"
            randomNumber[5] = ([5])
            answer[5] = "Fact5"
            for k in randomNumber:    <--- # now it's iterating over the dict, and since you wrote 1 first that is most likely to be the one it finds first in the memory though there no order here
                check_val(randomNumber[k], k, answer[k])


fact()

在Python中为字符串输出分配随机生成的整数

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