问题描述
我的问题是：如何限制错误的密码输入并将其作为功能？
我试图用范围 ，使其
if password == (password1):
print('Please wait')
print('Correct, logging in.')
exit
for password in range(5):
if password != (password1):
print('Please wait')
print('Incorrected, closing program.')
exit
但它会重复循环5次。
1楼
也许您正在寻找与此类似的东西？ 我不太确定！ 该程序将允许您在退出前输入5次错误的密码。
password1 = "hello"
i=0
while i<=4:
password = raw_input("Enter password: ")
if password1 == password:
print "Welcome"
break
else:
print "Try Again. %d tries left" %(4-i)
i+=1
else:
print "oops, you ran out of tries"
2楼
使用for .. in range循环，您可以要求用户在循环开始时重新输入，
from getpass import getpass
import random
import sys
import time
def validate_user_password(password, attempts=5):
for attempts_remaining in reversed(range(attempts)):
prompt='Please enter the password ({} attempts remaining): '.format(attempts_remaining + 1)
entry = getpass(prompt=prompt)
print('Please wait...')
# Wait random amount between 0.5s and 1s
time.sleep(random.uniform(0.5, 1))
if entry == password:
print('Correct, logging in.')
return True
else:
print('Incorrect password.')
# All attempts failed
return False
if __name__ == '__main__':
password = 'chewbacca'
if validate_user_password(password):
print('Admin powers unlocked. Here are the rocket launch codes: 1-2-3-4-5')
else:
print('Closing program.')
sys.exit(-1)
注意：getpass内置库隐藏了密码输入，因此，从您的肩膀往前看的人看不到您键入的内容。随机睡眠/等待是一种安全措施的示例，该措施有助于防止用户执行以下操作：使用定时攻击（在这种情况下可能不会有所帮助）。