问题描述
我的代码有问题，在这里：
correct = 0
grade_book = {}
File = open('Test.txt', 'r')
for line in File:
name, scores = line.split(':')
grade_book[name] = scores.strip()
File.close()
print(grade_book)
name = input("Name: ")
if name in grade_book.keys():
grade_book[name] += ',' + correct
else:
grade_book[name] = correct
File = open('Test.txt', 'w')
for name, scores in grade_book.items():
out_line = str(name) + ':' + str(scores) + "\n"
File.write(out_line)
File.close()
问题是它给出了错误说明：
TypeError：无法将“ int”对象隐式转换为str
当程序尝试将“正确”保存为文件中的现有名称时，就会在程序中发生这种情况。 我尝试使用以下方法解决此问题：
name = input("Name: ")
if name in grade_book.keys():
grade_book[name] += ',' + str(correct)
else:
grade_book[name] = correct
但是，这样做的问题是，尽管将“正确”分配给大于0的数字（例如8），但打印到文件的数字始终为0。另一方面，它确实会像以前一样给出错误，只是上面的问题。
有什么解决办法吗？
是的，我可能在这里错过了一些明显的东西。
“正确”的代码：
def mainLoop():
global count
global correct
Num1 = randint(1, 10)
Num2 = randint(1,10)
Operand= randint(1,3)
if Operand == 1:
question = str(Num1) + " + " + str(Num2) + " = "
answer = Num1 + Num2
elif Operand == 2:
question = str(Num1) + " - " + str(Num2) +" = "
answer = Num1 - Num2
else:
question = str(Num1) + " x " + str(Num2) + " = "
answer = Num1 * Num2
userAnswer = int(input(question))
if userAnswer == answer:
correct += 1
猜猜我将发布整个代码以供参考：
from random import randint
import time
count = 0
correct = 0
def mainLoop():
global count
global correct
Num1 = randint(1, 10)
Num2 = randint(1,10)
Operand= randint(1,3)
if Operand == 1:
question = str(Num1) + " + " + str(Num2) + " = "
answer = Num1 + Num2
elif Operand == 2:
question = str(Num1) + " - " + str(Num2) +" = "
answer = Num1 - Num2
else:
question = str(Num1) + " x " + str(Num2) + " = "
answer = Num1 * Num2
userAnswer = int(input(question))
if userAnswer == answer:
correct += 1
grade_book = {}
File = open('Test.txt', 'r')
for line in File:
name, scores = line.split(':')
grade_book[name] = scores.strip()
File.close()
print(grade_book)
name = input("Name: ")
if name in grade_book.keys():
grade_book[name] += ',' + str(correct)
else:
grade_book[name] = str(correct)
File = open('Test.txt', 'w')
for name, scores in grade_book.items():
out_line = str(name) + ':' + str(scores) + "\n"
File.write(out_line)
File.close()
while count < 10:
mainLoop()
count += 1
快了吗，可能是错的
文本文件示例： Test:1,5 John:1,0
1楼
将分数写入文件后，您正在运行mainLoop ，因此该文件将不包含正确的分数。
只需将询问问题的代码移动10遍（ while count < 10等等）到将分数写到grade_book的代码grade_book （ if name in grade_book.keys():等等）。
您可能会发现避免使用全局变量会有所帮助。
取而代之的是，您可以具有一个根据用户是否正确响应而返回True或False的问题函数，然后我们仅使用sum来计算正确和错误的响应。
from random import randint
import time
def question():
a = randint(1, 10)
b = randint(1,10)
operand= randint(1,3)
if operand == 1:
sign = '+'
answer = a + b
elif operand == 2:
sign = '-'
answer = a - b
else:
sign = 'x'
answer = a * b
user_answer = int(input('{} {} {} = '.format(a, sign, b)))
return user_answer == answer # returns True if correct, False if not
grade_book = {}
with open('Test.txt', 'r') as file:
for line in file:
name, scores = line.split(':')
grade_book[name] = scores.strip()
print(grade_book)
name = input("Name: ")
# Ask a question 10 times and sum up the correct responses
# (This works because sum counts True as 1 and False as 0)
correct = sum(question() for _ in range(10))
if name in grade_book.keys():
grade_book[name] += ',' + str(correct)
else:
grade_book[name] = str(correct)
with open('Test.txt', 'w') as file:
for name, scores in grade_book.items():
file.write('{}:{}\n'.format(name, scores))
2楼
在grade_book[name] = correct您可以分配整数值correct 。
因此应该是：
name = input("Name: ")
if name in grade_book.keys():
grade_book[name] += ',' + str(correct)
else:
grade_book[name] = str(correct)
而且您对“正确”不做任何事情。 总是0。