HDOJ 2133 What day is it

HDACM 2133

此题关键在于 1 1 1 是星期几 网上搜到的是 星期六
但是由此题推出是 星期一 所以要注意

import java.util.Scanner;public class Main{public static void main(String[] args) {int day[][] = {
   {
   0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 },{
   0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 }};String weekdays[] = { "Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday" };Scanner sc = new Scanner(System.in);while (sc.hasNext()) {int y = sc.nextInt();int m = sc.nextInt();int d = sc.nextInt();if (y <= 0 || y >= 10000 || m <= 0 || m >= 13 || d <= 0 || d >= 32) {System.out.println("illegal");continue;}if (isLeapYear(y)&&day[1][m]<d) {System.out.println("illegal");continue;}if (!isLeapYear(y)&&day[0][m]<d) {System.out.println("illegal");continue;}int ans = 0;for (int i = 1; i < y; i++) {if (isLeapYear(i)) {ans += 366;}else{ans += 365;}}for (int i = 1; i < m; i++) {if (isLeapYear(y)) {ans += day[1][i];}else{ans += day[0][i];}}ans += d;ans = ans % 7;System.out.println(weekdays[ans]);}sc.close();}public static boolean isLeapYear(int year) {if (year % 400 == 0 || year % 100 != 0 && year % 4 == 0) {return true;}return false;}
}