#include <iostream>
#include <vector>
#include <cmath>
using namespace std;int exist[100010]={0}, diff[100010] = {0};
// exist记录已经报过的数，diff记录已经报过的数的差值
vector<int> exists;
// exists记录已经报过的数，对于每个新报的数，和每个已存的数相减得差
int ht[15] = {0};
int a[1010][1010];int main() {int n1, n2;scanf("%d%d", &n1, &n2);diff[abs(n1 - n2)] = 1;exist[n1] = 1;exist[n2] = 1;exists.push_back(n1);exists.push_back(n2);int n, m;scanf("%d%d", &n, &m);for(int i = 1; i <= n; i++) for(int j = 1; j <= m; j++) scanf("%d", &a[i][j]); for(int j = 1; j <= m; j++) {for(int i = 1; i <= n; i++) {if(ht[i] == 1) continue;int t = a[i][j];if(diff[t] && !exist[t]) {for(int i = 0; i < exists.size(); i++) {int t2 = exists[i];diff[abs(t - t2)] = 1;}exist[t] = 1;exists.push_back(t);} else {ht[i] = 1;printf("Round #%d: %d is out.\n", j, i);}}}int f = 1;for(int i = 1; i <= n; i++) {if(ht[i] == 0) {if(f) printf("Winner(s):");printf(" %d", i);f = 0;}}if(f) printf("No winner.");return 0;
}
sad 考完补的 其实就是理顺了考试时候的思路（题目看懂却没写出来的估计就我一个白痴了……
测试样例过了，不知实际oj如何……