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Javascript 栈的应用:四则运算

热度:33   发布时间:2024-01-29 20:01:56.0

Javascript 栈的应用

四则运算式,先乘除后加减

//var x = '2+3*5-4';
1. 算法思路
低优先操作符遇到其右高优先级操作符,右侧先运算--------1
相同优先级的操作符,左侧优先运算------------2
高优先级操作符遇到其右低优先级操作符,左侧优先计算----3

例如

// 1+2+3;(2)
// 3+3
// 6

// 1+2*3(1)
// 1+6
// 7

// 1*2+3(3)
// 2+3
// 5

// 2+3*5-4-------------------(1)
// 2+15-4-------------------(2)
// 17-4--------------------(2)
// 13

// 对于每一个操作符,只有后面的操作符的优先级,高于当前操作符,遵循1原则,等待
// 等于,低于,遵循2原则,直接计算
// 2. 软件工程思路
// 2.1测试用例产生有限但是有效的测试用例,

//2+3*5-4
//1+2+3+4
//2*3*4*5
//1*2+3*4/2-4/2
//1+2
//2*3

//2.2要有debug的工具和手段,debug工具,或者log

// 栈,push - pop

var x = '2+3*5-4';
var nArray = [];
var oArray = [];var cl = 5;
var OPERATOR = [['+',0],['-',0],['*',1],['/',1]];var nRet = 0;
var iRet = '';
var i = 0; //pointer to current op//first number
var sNToken = x.charCodeAt(i) - 48;
var sPToken = '';
var nPriority = 0;
//'0' 30h 48    '9' 39h 57
if(sNToken < 0 || sNToken > 9){iRet = 'Error at position ' + i + ' : is not a number(' + x.charAt(i) + ')! Are you kidding me?';
}else{nArray.push(sNToken);//第一个数字压栈i = 1;for(;i<x.length;){//get the operatorsPToken = x.charAt(i);//-----validate the operatorfor(var j = 0;j < OPERATOR.length;j++){if(OPERATOR[j][0] == sPToken){break;}}if(j >=OPERATOR.length ){iRet = 'Error at position ' + i + ' : Syntax error: invalid operator \'' + sPToken + '\'';break;}//-----get the priority nPriority = OPERATOR[j][1];//get the second numbersNToken = x.charCodeAt(i+1) - 48;if(sNToken < 0 || sNToken > 9){iRet = 'Error at position ' + (i + 1) + ' : is not a number(' + x.charAt(i + 1) + ')! Are you kidding me?';break;}//compare the priority of the operatorwhile(oArray.length !=0 && oArray[oArray.length-1][1] >= nPriority){//弹栈计算var n;var n2 = nArray.pop();var n1 = nArray.pop();var op = oArray.pop()[0];switch(op){case '+':n = n1 + n2;break;case '-':n = n1 - n2;break;case '*':n = n1 * n2;break;case '/':n = n1 / n2;break;}if(!isFinite(n) || isNaN(n)){iRet = 'Error,the result is invalid!';break;}else{nArray.push(n);}}if(iRet){break;}//压栈nArray.push(sNToken);var opPair=[];opPair[0]=sPToken;opPair[1]=nPriority;oArray.push(opPair);i+=2;}//compare the priority of the operatorwhile(oArray.length !=0){//弹栈计算var n;var n2 = nArray.pop();var n1 = nArray.pop();var op = oArray.pop()[0];switch(op){case '+':n = n1 + n2;break;case '-':n = n1 - n2;break;case '*':n = n1 * n2;break;case '/':n = n1 / n2;break;}if(!isFinite(n) || isNaN(n)){iRet = 'Error,the result is invalid!';break;}else{nArray.push(n);}}
}
//check
if(iRet){console.log(iRet);//Error happens-------------to be added------------------------
}else{console.log(nRet=nArray.pop());
}

 

 

 

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