Asteroids【最小点覆盖】

Description–

Bessie wants to navigate her spaceship through a dangerous asteroid field in the shape of an N x N grid . The grid contains K asteroids, which are conveniently located at the lattice points of the grid.
Fortunately, Bessie has a powerful weapon that can vaporize all the asteroids in any given row or column of the grid with a single shot.This weapon is quite expensive, so she wishes to use it sparingly.Given the location of all the asteroids in the field, find the minimum number of shots Bessie needs to fire to eliminate all of the asteroids.
题目给出一个矩阵，上面有敌人，每个子弹可以打出一横行或者一竖行，问最少用多少子弹消灭都有敌人，如：
X.X
.X.
.X.

Input–

• Line 1: Two integers N and K, separated by a single space.
• Lines 2…K+1: Each line contains two space-separated integers R and C (1 <= R, C <= N) denoting the row and column coordinates of an asteroid, respectively.

Output–

• Line 1: The integer representing the minimum number of times Bessie must shoot.

Sample Input–

3 4
1 1
1 3
2 2
3 2

Sample Output–

2

说明–

1 <= N <= 500
1 <= K <= 10,000

代码–

#include <iostream>
#include <cstring>
#include <cstdio>using namespace std;int n, k, x, y, ans, l[105], f[105][105];
bool pd[105];bool find(int o)
{for (int i = 1; i <= n; ++i)if (f[o][i] && !pd[i]){pd[i] = 1;int e = l[i];l[i] = o;if (!e || find(e)) return 1;l[i] = e;}return 0;
}int main()
{scanf("%d%d", &n, &k);for (int i = 1; i <= k; ++i){scanf("%d%d", &x, &y);f[x][y] = 1;}for (int i = 1; i <= n; ++i){memset(pd, 0, sizeof(pd));if (find(i)) ans++;}printf("%d", ans);return 0;
}