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NYOJ - Triangular Sums

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Triangular Sums

时间限制: 3000 ms  |           内存限制: 65535 KB
难度: 2
描述

The nth Triangular number, T(n) = 1 + … + n, is the sum of the first n integers. It is the number of points in a triangular array withn points on side. For example T(4):

X
X X
X X X
X X X X

Write a program to compute the weighted sum of triangular numbers:

W(n) = SUM[k = 1…n;k * T(k + 1)]

输入
The first line of input contains a single integer N, (1 ≤ N ≤ 1000) which is the number of datasets that follow.

Each dataset consists of a single line of input containing a single integer n, (1 ≤ n ≤300), which is the number of points on a side of the triangle.
输出
For each dataset, output on a single line the dataset number (1 through N), a blank, the value of n for the dataset, a blank, and the weighted sum ,W(n), of triangular numbers for n.
样例输入
4
3
4
5
10
样例输出
1 3 45
2 4 105
3 5 210
4 10 2145
#include <stdio.h>
int main()
{int n,m,sign = 1;scanf("%d",&n);while(n--){scanf("%d",&m);int i,s = 0;for(i = 1; i <= m; i++){s += i*((i+1)*(i+2)/2);}printf("%d %d %d\n",sign++,m,s);}
}