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钥匙计数之二 HDU - 1480

热度:95   发布时间:2024-01-14 22:27:02.0

一把钥匙有N个槽,2<N<26槽深为1,2,3,4,5,6。每钥匙至少有3个不同的深度且相连的槽其深度之差不得为5。求这样的钥匙的总数。 

Input

本题无输入

Output

对2<N<26,输出满足要求的钥匙的总数。 

Sample Output

N=3: 104
N=4: 904
N=5: 5880
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N=25: 8310566473196300280
#include <iostream>
#include <stdio.h>
#include <string.h>
#include <queue>
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
ll dp[30][10][1<<7];
int flag;
ll dfs(int pos,int prev,int diff)
{int i;bitset<7> bit = diff;if(pos==0){if(bit.count()>=3) return 1;return 0;}if(dp[pos][prev][diff] != -1) return dp[pos][prev][diff];ll ans = 0;for(i=1;i<= 6;i++){bitset<7> nxt = bit;if(abs(i-prev) == 5&&pos != flag) continue;nxt[i] = 1;ans += dfs(pos-1,i,nxt.to_ulong());}dp[pos][prev][diff] = ans;return ans;
}
int main()
{memset(dp,-1,sizeof(dp));int i;for(i=3;i<=25;i++){flag = i;printf("N=%d: %lld\n",i,dfs(i,0,0));}return 0;
}