1、http://cdn.ac.nbutoj.com/Problem/view.xhtml?id=1219
2、比赛的时候居然想了一个小时，才意识到是3*3字符的含义，纠结，好在一遍AC了
题目：
-
[1219] Time
- 时间限制: 1000 ms 内存限制: 131072 K
- 问题描述
-
Digital clock use 4 digits to express time, each digit is described by 3*3 characters (including”|”,”_”and” “).now given the current time, please tell us how can it be expressed by the digital clock.
- 输入
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There are several test cases.
Each case contains 4 integers in a line, separated by space.
Proceed to the end of file. - 输出
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For each test case, output the time expressed by the digital clock such as Sample Output.
- 样例输入
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1 2 5 6 2 3 4 2
- 样例输出
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_ _ _ | _||_ |_ ||_ _||_|_ _ _ _| _||_| _| |_ _| ||_
- 提示
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The digits showed by the digital clock are as follows:_ _ _ _ _ _ _ _ | _| _||_||_ |_ ||_||_|| |||_ _| | _||_| ||_| _||_|
- 来源
-
辽宁省赛2010
#include<stdio.h>
#include<math.h>
#include<iostream>
#include<string.h>
#include<algorithm>
using namespace std;
int a[5];
int main()
{while(scanf("%d%d%d%d",&a[0],&a[1],&a[2],&a[3])!=EOF){for(int i=0; i<3; i++){for(int j=0; j<=3; j++){if(i==0){if(a[j]==1)printf(" ");else if(a[j]==2)printf(" _ ");else if(a[j]==3)printf(" _ ");else if(a[j]==4)printf(" ");else if(a[j]==5)printf(" _ ");else if(a[j]==6)printf(" _ ");else if(a[j]==7)printf(" _ ");else if(a[j]==8)printf(" _ ");else if(a[j]==9)printf(" _ ");else if(a[j]==0)printf(" _ ");}else if(i==1){if(a[j]==1)printf(" |");else if(a[j]==2)printf(" _|");else if(a[j]==3)printf(" _|");else if(a[j]==4)printf("|_|");else if(a[j]==5)printf("|_ ");else if(a[j]==6)printf("|_ ");else if(a[j]==7)printf(" |");else if(a[j]==8)printf("|_|");else if(a[j]==9)printf("|_|");else if(a[j]==0)printf("| |");}else if(i==2){if(a[j]==1)printf(" |");else if(a[j]==2)printf("|_ ");else if(a[j]==3)printf(" _|");else if(a[j]==4)printf(" |");else if(a[j]==5)printf(" _|");else if(a[j]==6)printf("|_|");else if(a[j]==7)printf(" |");else if(a[j]==8)printf("|_|");else if(a[j]==9)printf(" _|");else if(a[j]==0)printf("|_|");}} printf("\n");}}return 0;
}