Problem Description
Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as dog’s , cow’s , also he went to the grave …
The bone collector had a big bag with a volume of V ,and along his trip of collecting there are a lot of bones , obviously , different bone has different value and different volume, now given the each bone’s value along his trip , can you calculate out the maximum of the total value the bone collector can get ?
Input
The first line contain a integer T , the number of cases.
Followed by T cases , each case three lines , the first line contain two integer N , V, (N <= 1000 , V <= 1000 )representing the number of bones and the volume of his bag. And the second line contain N integers representing the value of each bone. The third line contain N integers representing the volume of each bone.
Output
One integer per line representing the maximum of the total value (this number will be less than 231).
Sample Input
1
5 10
1 2 3 4 5
5 4 3 2 1
Sample Output
14
#include <cstdio>
#include <algorithm>
#include <cstring>
using namespace std;
int main()
{int t,n,v,i[1005],j[1005],dp[1005];scanf("%d",&t);while(t --){scanf("%d%d",&n,&v);memset(dp,0,sizeof(dp));for(int a = 0; a < n; a ++)scanf("%d",&j[a]);for(int a = 0; a < n; a ++)scanf("%d",&i[a]);for(int a = 0; a < n; a ++){for(int b = v; b >= i[a]; b --)dp[b]=max(dp[b],dp[b-i[a]]+j[a]);}for(int a = 0; a <= v; a ++)dp[0]=max(dp[0],dp[a]);printf("%d\n",dp[0]);}return 0;
}