How many days?
Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 8506 Accepted Submission(s): 4922
Problem Description
8600的手机每天消费1元，每消费K元就可以获赠1元，一开始8600有M元，问最多可以用多少天？
Input
输入包括多个测试实例.每个测试实例包括2个整数M, k，（2 <= k <= M <= 1000).M = 0, k = 0代表输入结束.
Output
对于每个测试实例输出一个整数，表示M元可以用的天数。
Sample Input
2 2 4 3 0 0
Sample Output
3 5
import java.util.Scanner;public class Main{private static Scanner scanner;public static void main(String[] args) {scanner = new Scanner(System.in);while (scanner.hasNext()) {int m = scanner.nextInt();int k = scanner.nextInt();if (m == 0 && k == 0) {break;}int day = 0;while (true) {for (int i = 0; i < k; i++) {// 每次减k元，每减一元如果day>=0就day++// 否则就是负数了，退出form--;if (m >= 0) {day++;} else {break;}}// 到这里如果大于等于0，证明消费满了k次，day应该++// 否则就应该退出if (m >= 0) {m++;} else {break;}}System.out.println(day);}}
}