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SpringBoot + CXF快速实现SOAP WebService(支持Basic Auth)

热度:70   发布时间:2023-12-13 11:19:31.0

讲真,SOAP跟现在流行的RESTful WebService比起来显得很难用。冗余的XML文本信息太多,可读性差,它的请求信息有时很难手动构造,不太好调试。不过说归说,对某些企业用户来说SOAP的使用率仍然是很高的。

 一、需求背景

接手维护的一个项目,最近客户想开放项目中的功能给第三方调用,而且接入方指定必须是SOAP接口。这项目原来的代码我看着头疼,也不想再改了,除非推倒重写。客户的需求虽然不难但要的很急,为了尽快交付就使用SpringBoot快速搭一个微服务。

二、创建Maven示例工程

1.新建一个Spring Starter Project
2.加入cxf的maven配置
<dependency><groupId>org.apache.cxf</groupId><artifactId>cxf-spring-boot-starter-jaxws</artifactId><version>3.1.15</version>
</dependency>

三、编写服务代码

@WebService(targetNamespace="http://demo.example.com/")
public interface IUserService {@WebMethodUser getUserById(@WebParam(name = "id") int id);@WebMethodint addUser(@WebParam(name = "user") User user);
}
@InInterceptors(interceptors={"com.example.demo.auth.AuthInterceptor"})
@WebService(serviceName = "UserService", targetNamespace = "http://demo.example.com/", endpointInterface = "com.example.demo.soap.IUserService")
@Component
public class UserServiceImpl implements IUserService {private Logger logger = LoggerFactory.getLogger(UserServiceImpl.class);@Autowiredprivate IUserDAO userDAO;@Overridepublic User getUserById(int id) {return userDAO.getUserById(id);}@Overridepublic int addUser(User user) {logger.info("save user [" + user.getId() + "]");userDAO.addUser(user);return 0;}
}

鉴权拦截器

public class AuthInterceptor extends AbstractSoapInterceptor {private static final String BASIC_PREFIX = "Basic ";private static final String USERNAME = "lichmama";private static final String PASSWORD = "123456";public AuthInterceptor() {super(Phase.PRE_INVOKE);}@Overridepublic void handleMessage(SoapMessage message) throws Fault {HttpServletRequest request = (HttpServletRequest) message.get(AbstractHTTPDestination.HTTP_REQUEST);String auth = request.getHeader("Authorization");if (auth == null) {SOAPException exception = new SOAPException("auth failed, header [Authorization] not exists");throw new Fault(exception);}if (!auth.startsWith(BASIC_PREFIX)) {SOAPException exception = new SOAPException("auth failed, header [Authorization] is illegal");throw new Fault(exception);}String plaintext = new String(Base64.getDecoder().decode(auth.substring(BASIC_PREFIX.length())));if (StringUtils.isEmpty(plaintext) || !plaintext.contains(":")) {SOAPException exception = new SOAPException("auth failed, header [Authorization] is illegal");throw new Fault(exception);}String[] userAndPass = plaintext.split(":");String username = userAndPass[0];String password = userAndPass[1];if (!USERNAME.equals(username) || !PASSWORD.equals(password)) {SOAPException exception = new SOAPException("auth failed, username or password is incorrect");throw new Fault(exception);}}
}

编写配置类

@Configuration
public class SoapConfig {@Autowiredprivate IUserService userService;@Autowired@Qualifier(Bus.DEFAULT_BUS_ID)private SpringBus bus;@Beanpublic Endpoint endpoint() {EndpointImpl endpoint = new EndpointImpl(bus, userService);endpoint.publish("/userService");return endpoint;}
}

修改CXF默认发布路径(application.properties)

server.port=8000
cxf.path=/soap

四、启动运行服务

启动项目后访问http://localhost:8000/soap/userService?wsdl

使用SoapUI测试一下,看上去没什么问题

客户端增加对Basic Auth的支持:

/*使用Eclipse自动生成Web Service Client,在SoapBingdingStub的createCall()方法中加入一下代码:
*/// basic auth
_call.setProperty("javax.xml.rpc.security.auth.username", "lichmama");
_call.setProperty("javax.xml.rpc.security.auth.password", "123456");

然后正常调用即可,这里提供一下自己写的SoapClient:

public class GeneralSoapClient {private String WSDL;private String namespaceURI;private String localPart;public GeneralSoapClient() {}public GeneralSoapClient(String WSDL, String namespaceURI, String localPart) {this.WSDL = WSDL;this.namespaceURI = namespaceURI;this.localPart = localPart;}public String getWSDL() {return WSDL;}public void setWSDL(String WSDL) {this.WSDL = WSDL;}public String getNamespaceURI() {return namespaceURI;}public void setNamespaceURI(String namespaceURI) {this.namespaceURI = namespaceURI;}public String getLocalPart() {return localPart;}public void setLocalPart(String localPart) {this.localPart = localPart;}private boolean requireAuth = false;private String username;private String password;public boolean isRequireAuth() {return requireAuth;}public void setRequireAuth(boolean requireAuth) {this.requireAuth = requireAuth;}public String getUsername() {return username;}public void setUsername(String username) {this.username = username;}public String getPassword() {return password;}public void setPassword(String password) {this.password = password;}/*** 创建Soap Service实例* @param serviceInterface* @return* @throws Exception*/public <T> T create(Class<T> serviceInterface) throws Exception {URL url = new URL(WSDL);QName qname = new QName(namespaceURI, localPart);Service service = Service.create(url, qname);T port = service.getPort(serviceInterface);if (requireAuth) {BindingProvider prov = (BindingProvider) port;prov.getRequestContext().put(BindingProvider.USERNAME_PROPERTY, username);prov.getRequestContext().put(BindingProvider.PASSWORD_PROPERTY, password);}return port;}
}
public class TestSoap {public static void main(String[] args) throws Exception {String wsdl = "http://localhost:8080/soap/userService?wsdl";String namespaceURI = "http://demo.example.com/";String localPart = "UserService";GeneralSoapClient soapClient = new GeneralSoapClient(wsdl, namespaceURI, localPart);soapClient.setRequireAuth(true);soapClient.setUsername("lichmama");soapClient.setPassword("123456");IUserService service = soapClient.create(IUserService.class);User user = service.getUserById(101);}
}

最后交代一下开发环境

STS 3.7.3 + SpringBoot 2.0.1 + JDK1.8

 

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