quadratic equation
Time Limit: 2000MS
Memory Limit: 131072KB
Submit Statistic
Problem Description
With given integers a,b,c, you are asked to judge whether the following statement is true: "For any x, if a?+b?x+c=0, then x is an integer."
Input
The first line contains only one integer T(1≤T≤2000), which indicates the number of test cases.
For each test case, there is only one line containing three integers a,b,c(?5≤a,b,c≤5).
Output
or each test case, output “YES” if the statement is true, or “NO” if not.
Example Input分析
3 1 4 4 0 0 1 1 3 1
Example Output
YES YES NO
Hint
Author
“浪潮杯”山东省第八届ACM大学生程序设计竞赛（感谢青岛科技大学）
分析：会if就能做，条件判断入门题
#include <bits/stdc++.h>using namespace std;int main()
{int t;cin>>t;while(t--){int a,b,c;cin>>a>>b>>c;if(a==0 && b==0 ){if(c==0){puts("NO");continue;}else{puts("YES");continue;}}else if(a==0 && b!=0){if(c%b !=0){puts("NO");continue;}else{puts("YES");continue;}}else if(a!=0){int dt=b*b-4*a*c;if(dt<0){puts("YES");continue;}else{double kg=sqrt(dt);if(((-b+kg)/(2*a)) - (int)((-b+kg)/(2*a))==0 && ((-b-kg)/(2*a))- (int)((-b-kg)/(2*a))==0 ){puts("YES");continue;}else{puts("NO");continue;}}}}return 0;
}