Implicit intents with startService are not safe错误的解决方式_综合

原文链接：http://www.eoeandroid.com/thread-568853-1-1.html

有些时候我们使用Service的时需要采用隐私启动的方式，但是Android 5.0一出来后，其中有个特性就是Service Intent must be explitict，也就是说从Lollipop开始，service服务必须采用显示方式启动。

而android源码是这样写的（源码位置：sdk/sources/android-21/android/app/ContextImpl.java）：

     private void validateServiceIntent(Intent service) {if (service.getComponent() == null && service.getPackage() == null) {if (getApplicationInfo().targetSdkVersion >= Build.VERSION_CODES.LOLLIPOP) {IllegalArgumentException ex = new IllegalArgumentException("Service Intent must be explicit: " + service);throw ex;} else {Log.w(TAG, "Implicit intents with startService are not safe: " + service+ " " + Debug.getCallers(2, 3));}}}

那么这里有两种解决方法：

1、设置Action和packageName：

参考代码如下：

    Intent mIntent = new Intent();mIntent.setAction("XXX.XXX.XXX");//你定义的service的actionmIntent.setPackage(getPackageName());//这里你需要设置你应用的包名context.startService(mIntent);

此方式是google官方推荐使用的解决方法。
在此附上地址供大家参考：http://developer.android.com/goo ... tml#billing-service,有兴趣的可以去看看。

2、将隐式启动转换为显示启动：--参考地址：http://stackoverflow.com/a/26318757/1446466

    public static Intent getExplicitIntent(Context context, Intent implicitIntent) {// Retrieve all services that can match the given intentPackageManager pm = context.getPackageManager();List<ResolveInfo> resolveInfo = pm.queryIntentServices(implicitIntent, 0);// Make sure only one match was foundif (resolveInfo == null || resolveInfo.size() != 1) {return null;}// Get component info and create ComponentNameResolveInfo serviceInfo = resolveInfo.get(0);String packageName = serviceInfo.serviceInfo.packageName;String className = serviceInfo.serviceInfo.name;ComponentName component = new ComponentName(packageName, className);// Create a new intent. Use the old one for extras and such reuseIntent explicitIntent = new Intent(implicitIntent);// Set the component to be explicitexplicitIntent.setComponent(component);return explicitIntent;}

调用方式如下：

    Intent mIntent = new Intent();mIntent.setAction("XXX.XXX.XXX");Intent eintent = new Intent(getExplicitIntent(mContext,mIntent));context.startService(eintent);