id score
1 55
1 65
1 80
2 60
2 55
2 88
如何查询出来是
id s1 s2 s3
1 55 65 80
2 60 55 88
------解决方案--------------------
- SQL code
--我寫的這個有點復雜,等高人幫你寫個簡單的吧with t(id,score) as(select 1,55 from dualunion all select 1,65 from dualunion all select 1,80 from dualunion all select 2,60 from dualunion all select 2,65 from dualunion all select 2,88 from dual)select id, max(decode(rn,1,score,0)) s1, max(decode(rn,2,score,0)) s2, max(decode(rn,3,score,0)) s3from (select row_number() over(partition by id order by id) rn,id,score from t) group by id;/* ID S1 S2 S3 ---------- ---------- ---------- ---------- 1 55 65 80 2 60 65 88 */
------解决方案--------------------
with t(id,score) as(
select 1,55 from dual
union all select 1,65 from dual
union all select 1,80 from dual
union all select 2,60 from dual
union all select 2,65 from dual
union all select 2,88 from dual
)
SELECT * FROM (select id as fid,score,row_number()over(partition by id order by id) as rn from t ) t1
pivot(SUM(score) FOR rn IN (1,2,3))
FID 1 2 3
---------------------- ---------------------- ---------------------- ----------------------
1 55 65 80
2 60 65 88