问题描述
我从客户端发送了以下查询字符串参数
{"take":75,"skip":0,"page":1,"pageSize":75,"filter":{"logic":"and","filters":
[{"field":"prodCode","operator":"eq","value":"Z20"}]}}:
在REST服务器中,如何接收以上格式并正确分配给每个类别?
更新1
MultivaluedMap params = uriInfo.getQueryParameters();
参数的值是
{_ = [1437904506062],{“ take”:75,“ skip”:0,“ page”:1,“ pageSize”:75,“ filter”:{“ logic”:“ and”,“ filters”:[ { “字段”: “prodCode”, “运算符”: “当量”, “值”: “Z30”}]}} = []}
1楼
这是一个查询参数因此必须使用得到它key
具有其值作为{"take":75,"skip":0,"page":1,"pageSize":75,"filter":{"logic":"and","filters": [{"field":"prodCode","operator":"eq","value":"Z20"}]}}:
。
因此,使用该key
,将以上内容存储在String
,然后解析为JSON
(我在这里使用org.json
)。
您将可以根据需要提取任何key
/ value
。
您可以使用代码段:-
String inputValue = @QueryParam(YOUR_KEY); // OR whatever way you get it
/*
* This inputValue will actually contain your value :-
* {"take":75,"skip":0,"page":1,
* "pageSize":75,"filter":{"logic":"and","filters":
* [{"field":"prodCode","operator":"eq","value":"Z20"}]}}
*/
JSONObject inputJSON = new JSONObject(inputValue);
//Now getting values from input JSON
int take = inputJSON.getInt("take");
int skip = inputJSON.getInt("skip");
int page = inputJSON.getInt("page");
int pageSize = inputJSON.getInt("pageSize");
JSONObject filter = inputJSON.getJSONObject("filter"); // filter is again a JSONObject
String logic = filter.getString("logic");
System.out.println(take + " "+skip + " "+page + " "+pageSize + " "+logic);
JSONArray filters = filter.getJSONArray("filters"); // filters is a JSONArray
for(int i = 0; i< filters.length(); i++){ // iterating over JSONArray
JSONObject jo = (JSONObject)filters.get(i);
String field = jo.getString("field");
String operator = jo.getString("operator");
String value = jo.getString("value");
System.out.println(field + " "+operator + " "+value );
}
输出:-
75 0 1 75 and
prodCode eq Z20