怎么返回上一层？

import java.util.*;
    public class test{
        public static void main(String[] args){
            System.out.println("请按提示输入！");
            System.out.println("1、查询余额2、取款3、转账、4、退出取卡");
            Scanner input=new Scanner(System.in);
            int money=input.nextInt();

            //想在这里加个循环，让它第四次的时候重新输入，并且输入次数有限为三！怎么做？
                switch(money){
            
                    
                    case 1:
                        System.out.println("这是500元，请收好！");
                                                    
                            
                        break;
                    case 2:
                        System.out.println("请输入要转账的金额：");
                        System.out.println("请输入要转账的账号：");
                        break;
                    case 3:
                        System.out.println("请将卡收好！");
                        break;
                    case 4:
                        System.out.println("输入有误！请重新输入！");
                }
                
            }        
        }
        
}
----------------解决方案--------------------------------------------------------
public static void main(String[] args)
    {
        // TODO Auto-generated method stub
        boolean isContinue = true;
        int count = 0;
        while(isContinue && count < 3)
        {
            System.out.println("make your choice");
            int choice;
            read in choice here
            
            switch(choice)
            {
                case 1: ****;
                        break;
                case 2: ****;
                         break;
                case 3: ****;
                        break;
                case 4: ****;
                        break;
                default : should never reach here;
                          break;
            }
            
            String wantContinue;
            println("continue ?  yes or No")
            read in wantContinu;
            if("yes".equals(wantContinue.toLowerCase()))
            {
                isContinue = true;
                count++;
            }
            else if("no".equals(wantContinue.toLowerCase()))
            {
                isContinue = false;
            }
            else
            {
                println(wrong answer);
                exit(1);
            }
        }
    }
----------------解决方案--------------------------------------------------------
"让它第四次的时候重新输入，并且输入次数有限为三！"
看不懂...
有限为三,怎么还有第四次重新输入?
----------------解决方案--------------------------------------------------------