大家帮忙看一下这个程序哪里出错了，谢谢了！！！

import javax.swing.*;
public class Test
{
int num1,num2;
while(true)//illegal start of type
{
num1=Integer.parseInt(JOptionPane.showInputDialog("Enter a number please:"));
num2=Integer.parseInt(JOptionPane.showConfirmDialog("Enter another number please:"));
if(num2!=0&&num1/num2>=10)
System.out.println(num1/num2);
else
System.out.print("The result is less than 10!");

}
}//<identifier> expected

----------------解决方案--------------------------------------------------------
添加了main（）函数，又出现了一个错误：
import javax.swing.*;
public class Test
{
public static void main(String args[])
{

int num1,num2;
while(true)
{
num1=Integer.parseInt(JOptionPane.showInputDialog("Enter a number please:"));
num2=Integer.parseInt(JOptionPane.showConfirmDialog("Enter another number please:"));//cannot result symbol method showConfirmDialog(java.lang.String)
if(num2!=0&&num1/num2>=10)
System.out.println(num1/num2);
else
System.out.print("The result is less than 10!");
}
}
}
这是什么错误呀？谢谢！！


----------------解决方案--------------------------------------------------------
晕死，我知道哪里错了。
----------------解决方案--------------------------------------------------------

怎么看都象死循环

----------------解决方案--------------------------------------------------------

看看这样行不行？
import javax.swing.*;
public class Test
{
public static void main(String args[])
{

int num1,num2;
boolean f;
while(f==true)
{
num1=Integer.parseInt(JOptionPane.showInputDialog("Enter a number please:"));
num2=Integer.parseInt(JOptionPane.showConfirmDialog("Enter another number please:"));//cannot result symbol method showConfirmDialog(java.lang.String)
if(num2!=0 && num1/num2>=10)
{f=true
System.out.println(num1/num2);
}
else
System.out.print("The result is less than 10!");
}
}
}

----------------解决方案--------------------------------------------------------

import javax.swing.*;
public class test
{
public static void main(String args[])
{

int num1,num2;
num1=Integer.parseInt(JOptionPane.showInputDialog("Enter a number please:"));
num2=Integer.parseInt(JOptionPane.showInputDialog("Enter another number please:"));
if(num2!=0&&num1/num2>=10)
System.out.println(num1/num2);
else
System.out.print("The result is less than 10!");
}
}
showConfirmDialog不能那样用呀……所以会错，我不想无限的输入数字……所以我把while去掉了

----------------解决方案--------------------------------------------------------