【求助】使用jaxb怎么序列化 List对象啊_J2SE

【求助】使用jaxb如何序列化 List对象啊

Java code

List<Book> books =new ArrayList<Book>();Book book=new Book();book.setName="书名1";book.setContent="内容1";Book book2=new Book();book2.setName="书名2";book2.setContent="内容2";books.add(book);books.add(book2);

请问使用jaxb 如何实现 list 和xml之间的相互转化？？
非常感谢

------解决方案--------------------
book类

Java code

private String name;    private String content;    public String getName() {        return name;    }    public void setName(String name) {        this.name = name;    }    public String getContent() {        return content;    }    public void setContent(String content) {        this.content = content;    }
------解决方案--------------------
Book.java
Java code@XmlType(propOrder={"name","content"})@XmlRootElement(name="book")public class Book {    private String name;    private String content;    @XmlElement    public final String getContent() {        return content;    }    public final void setContent(final String content) {        this.content = content;    }    @XmlElement    public final String getName() {        return name;    }    public final void setName(final String name) {        this.name = name;    }}