求救 java解析html,该怎么处理_J2SE

求救 java解析html
求救，java用哪个类可以解析html里面的标签啊，例如我要解析html里面的<a href=""></a>，用哪个类啊？

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jdom
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htmlparse组件
或者正则
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正则表达式
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比如我想获得http://csbbs.soufun.com/2710156784~-2~683/5236858_5236858.htm网址中社区这个标签的联结地址，可以这样

Java code

import java.net.*;import java.util.regex.Matcher;import java.util.regex.Pattern;import java.io.*;public class UrlCodeRegex{  public static void main(String[] args)   {    try     {        String ur="http://csbbs.soufun.com/2710156784~-2~683/5236858_5236858.htm"; //获取远程网上的信息        URL MyURL=new URL(ur);        String str;        URLConnection con=MyURL.openConnection();        InputStreamReader ins=new InputStreamReader(con.getInputStream());        BufferedReader in=new  BufferedReader(ins);        StringBuffer sb = new StringBuffer();        while ((str=in.readLine())!=null)        {              sb.append(str);        }            in.close();                        Pattern p = Pattern.compile(".*<a href=\"(.*)\">社区</a>.*");            Matcher m  = p.matcher(sb.toString());            m.matches();            System.out.println("这个社区的网址是"+m.group(1));     }    catch (MalformedURLException mfURLe) {      System.out.println("MalformedURLException: " + mfURLe);    }    catch (IOException ioe) {      System.out.println("IOException: " + ioe);    }  }}
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JDK自带的javax.swing.text.html.parser这个包
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或者这个更好
Java code /** * 此程序是获得网页源代码中某个关键字的链接网址， * 如<a href="http:\\www.sina.com" target="blank">新浪</a> */import java.net.*;import java.util.regex.Matcher;import java.util.regex.Pattern;import java.io.*;public class UrlCodeRegex{  public static void main(String[] args)   {    try     {        String ur="http://csbbs.soufun.com/2710156784~-2~683/5236858_5236858.htm"; //获取远程网上的信息        URL MyURL=new URL(ur);        String str;        URLConnection con=MyURL.openConnection();        InputStreamReader ins=new InputStreamReader(con.getInputStream());        BufferedReader in=new  BufferedReader(ins);        StringBuffer sb = new StringBuffer();        while ((str=in.readLine())!=null)        {              sb.append(str);        }            in.close();                          Pattern p = Pattern.compile(".*<a href=\"(http://([\\w-]+\\.)+[\\w-]+(/[\\w- ./?%&=]*)?)\".*>社区</a>.*");            Matcher m  = p.matcher(sb.toString());            m.matches();            System.out.println("这个社区的网址是"+m.group(1));     }    catch (MalformedURLException mfURLe) {      System.out.println("MalformedURLException: " + mfURLe);    }    catch (IOException ioe) {      System.out.println("IOException: " + ioe);    }  }}
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用  javax.xml.parsers.SAXParser
自己写个 handler 就好了！ 像这样

Java code    public static void main(String[] args)throws Exception{        SAXParserFactory factory = SAXParserFactory.newInstance();        factory.setNamespaceAware(true);        SAXParser parser = factory.newSAXParser();        URL url = new URL("xxxx");//xxxx is you URL        URLConnection con = url.openConnection();        MyHandler myhandler = new MyHandler();        parser.parse(con.getInputStream(), myhandler);        System.out.println(myhandler.list);    }class MyHandler extends DefaultHandler{    public ArrayList list = new ArrayList();    public void startElement(String s, String s1, String s2,            Attributes attributes) throws SAXException {        if(s.equals("a")||s1.equals("a")){            list.add(attributes.getValue("href"));        }    }}