不要用API来糊弄我，我要的是能够解决问题的答案
服务器代码
import java.net.*;
import java.io.*;
public class serverTCP
{
public static void main(String[] args)
{
try{
ServerSocket serversocket=new ServerSocket(2000);
Socket socket=serversocket.accept();
BufferedReader buffer=new BufferedReader(new InputStreamReader(socket.getInputStream()));
String s=buffer.readLine();
System.out.print(s);
socket.close();
}catch(SocketException e){e.printStackTrace();}
catch(IOException e1){e1.printStackTrace();}
catch(UnknownHostException e2){e2.printStackTrace();}
}
}
客户端代码
import java.net.*;
import java.io.*;
public class clientTCP
{
public static void main(String[] args)
{
try{
Socket socket=new Socket(InetAddress.getByName("localhost"),2000);
PrintWriter out=new PrintWriter(new BufferedWriter(new OutputStreamWriter(socket.getOutputStream())),true);
out.print("我向你发送了一个连接请求,你收到了吗");
}catch(SocketException e){e.printStackTrace();}
catch(IOException e1){e1.printStackTrace();}
}
}
错误：
当我运行客户端代码时会向服务器端发送一个字符串；
这时服务器端程序出现异常错误：
这是怎么回事，是我没有捕捉异常吗。
我应该怎么修改服务器端的代码：？
不要用API来糊弄我，我要的是能够解决问题的答案
------解决方案--------------------
- Java code
import java.net.*;import java.io.*;public class serverTCP { public static void main(String[] args) { ServerSocket serversocket = null; Socket socket = null; BufferedReader buffer = null; try { serversocket = new ServerSocket(2000); socket = serversocket.accept(); buffer = new BufferedReader(new InputStreamReader( socket.getInputStream())); String s = buffer.readLine(); System.out.print(s); buffer.close(); socket.close(); } catch (SocketException e) { e.printStackTrace(); } catch (IOException e1) { e1.printStackTrace(); } finally { try { buffer.close(); socket.close(); serversocket.close(); } catch (IOException e) { // TODO 自动生成 catch 块 e.printStackTrace(); } } }}