一道程序题!解决方法_J2SE

一道程序题!!
比如有一个数99,那么就打印连续数相加等于99的数
99=[4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14]
99=[7, 8, 9, 10, 11, 12, 13, 14, 15]
99=[14, 15, 16, 17, 18, 19]
99=[32, 33, 34]
99=[49, 50]

写出实现代码!

------解决方案--------------------
不是算法不知道是这样不

Java code

public class AddNum {    public static void main(String args[]) {        int num = 99;        int mid = num / 2 + 1;        int sum = 0;        int start, end;        for (int i = 0; i < mid + 1; i++) {            start = i;            for (int j = i + 1; j < mid + 1; j++) {                sum = sum + j;                if (sum == num) {                    end = j;                    System.out.println(start + 1 + "-----" + end);                }            }            sum = 0;        }    }}
------解决方案--------------------
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Java code

public void printNums(int totalNum){
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        if( (totalNum - n*(n-1)/2)%n !=0 )
            continue;
        else{
            a = (totalNum ……