- Java code
package holding;import static net.mindview.util.Print.print;import java.util.HashMap;import typeinfo.pets.Person;import typeinfo.pets.Pet;public class KeepCount extends HashMap{ static KeepCount kc=new KeepCount(); public void add() { this.put("good","99.9" ); this.put("bad","10" ); this.put("soso","70" ); this.put("good","90" ); this.put("good","86" ); this.put("bad","50" ); this.put("soso","60" ); this.put("soso","84" ); this.put("good","99" ); this.put("bad","40" ); this.put("bad","56" ); this.put("soso","71" ); this.put("good","87" ); this.put("bad","51" ); this.put("soso","65" ); this.put("good","100" ); } public static void main(String[] args) { kc.add(); System.out.println(kc); for(Object person : kc.keySet()) { print(person); for(Object pet : kc.get(person)) //这行错了,说什么不能迭代什么的 print(" " + pet); } }}
------解决方案--------------------
for(Object person : kc.keySet()) {//kc.keySet()对kc这个map的key组成的list进行迭代
print(person);//person是其中的一个key
for(Object pet : kc.get(person)) //kc.get(person)是kc中key为person所对应的map值,他就是一个value,所以不能迭代
print(" " + pet);
}