怎么生成一个10位的整数字符串不满10位的补0　如0003214561

public String convert(int n){    String s = "" + n;    for(int i = s.length();i < 10;i++){         s = '0' + s;    }    return s;}
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同问有简单的没？
Java code
import java.util.*;public   class   test   {public   static   void   main(String   args[]){   Random rand=new Random();   StringBuilder sb=new StringBuilder();   String x;   x=rand.nextInt(999999999)+"";   int i=10-x.length();   while(i>0){       sb.append("0");       i--;   }   sb.append(x);   System.out.println(sb.toString());}}
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import   java.util.*;  
public   class   compare  
{  
   public   static   void   main(String[]args)  
   {  
     S
   	System.out.println(new compare().getResult());
     }
     public Integer getLength(){
   	  Random ran = new Random();
   	 
   	  int len = ran.nextInt(10);
   	  return len;
     }
     public String getResult(){
   	  Random ran = new Random();
   	  String returnValue ="";
   	  int len =getLength();
   	  for(int i=1;i<=len;i++){
   		  Integer chara=ran.nextInt(10);
   		  returnValue+=chara.toString();
   	  }
   	  if(len<10)
   	  {
   		  returnValue="0000000000".substring(0,10-len)+returnValue;
   	  }
   	  return returnValue;
   	 
     }
}
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import java.text.DecimalFormat;


public class Main {

	public static void main(String[] args)
	{
		int i = 3214561;
		DecimalFormat df = new DecimalFormat("0000000000");
		System.out.println(df.format(i));
	}
}
哦。不好意思。开始理解错了意思。原来不是要输出啊。那就用这个吧。。。
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名有特色