3条语句搞定一亿数据获取前100个最大值,该如何解决

        Random rand = new Random();        PriorityQueue<Integer> P = new PriorityQueue<Integer>();        for(int i = 0,num = rand.nextInt(); (i < 100 && P.add(num)) || (i < 100000000 && (P.peek() < num && P.add(num) && P.remove() != null || 1==1)); i++,num = rand.nextInt());        //System.out.println(P);