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Hibernnate的one-to-mang,该如何解决

热度:308   发布时间:2016-04-22 00:36:53.0
Hibernnate的one-to-mang
[code=Java][/code]
<hibernate-mapping>
  <class name="qh.merchinfo.Merchinfo" table="MERCHINFO" lazy="false">
  <id name="merchId" type="java.lang.String">
  <column name="MERCH_ID" length="20" />
  <generator class="assigned"></generator>
  </id>
  <property name="merchname" type="java.lang.String">
  <column name="MERCHNAME" length="50" not-null="true" />
  </property>
  <property name="merchprice" type="double">
  <column name="MERCHPRICE" precision="6" />
  </property>
  <property name="importprice" type="double">
  <column name="IMPORTPRICE" precision="6" />
  </property>
  <property name="provideId" type="java.lang.String">
  <column name="PROVIDE_ID" length="20" not-null="true" />
  </property>
  <property name="colorclass" type="java.lang.String">
  <column name="COLORCLASS" length="20" />
  </property>
  <property name="styleclass" type="java.lang.String">
  <column name="STYLECLASS" length="20" />
  </property>
  <property name="clothessize" type="java.lang.String">
  <column name="CLOTHESSIZE" length="20" />
  </property>
  <property name="barcode" type="java.lang.String">
  <column name="BARCODE" length="50" />
  </property>
  <property name="salesstart" type="date">
  <column name="SALESSTART" length="23" />
  </property>
  <property name="salesend" type="date">
  <column name="SALESEND" length="23" />
  </property>

  </class>  
</hibernate-mapping>

在反向工程的时候,如果选上多对一后面就会报错。现在我在做B/S程序是,不能删除被引用的主表信息,不知道怎么样配置<set> </set>

------解决方案--------------------
举个例子: <!-- column 外键 
inverse 放弃控制权(不去维护关系 )
-->
<set name="jds" inverse="true" cascade="all">
<key column="qxid"></key>
<one-to-many class="pojo.TblJd"/>
</set>