在程序中写入太多的System.out.println();怎么定义一个字符串。
我想要的是y="Good moring" System.out.println(y);
这样的效果,请问怎么定义y?
这是代码import java.util.*;
public class y{
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
System.out.println(" *****Tine table*****");
System.out.println(" 1 moring ");
System.out.println(" 2 afternoon ");
System.out.println(" 3 night ");
System.out.println("Please enter your choice ");
Scanner sc=new Scanner(System.in);
int x;
x=sc.nextInt();
switch (x){case 1:
System.out.println("Good moring");break;
case 2:
System.out.println("Good afternoon");break;
case 3:
System.out.println("Good night");break;
default:
System.out.println("Sleection error");
}
}
}
------最佳解决方案--------------------
String a="string";
String a=new String("string");
String a=1+"="+1;