循环问题！！

while(1)
  {
    printf("\nPlease enter the car\'s id you want to modify:");
    scanf("%ld",&m);
    switch(a=(array1[0].id<=m&&m<=array1[t-1].id))
     {
      case 0:printf("\nError input!\n");break;
      case 1:d=search(m,array1);
             strcpy(z,array1[d].name);
             printf("\n\tPlease enter the name you want:\n");
             scanf("%s",array1[d].name);
             if(strcmp(z,array1[d].name)==0)
               printf("\nFail!");
             else
               printf("\nSuccessful!");
             break;
     }
    printf("\n\tPress \'Q\' to quit!\n");
    s=getchar();
    if(s=='q'||s=='Q')
      break;
   }
这是函数的一部分，为什么这里
    printf("\n\tPress \'Q\' to quit!\n");
    s=getchar();
    if(s=='q'||s=='Q')
      break;
不能实现，运行后跳过了s=getchar()之后的语句。
----------------解决方案--------------------------------------------------------
经再次研究，这里
    printf("\n\tPress \'Q\' to quit!\n");
    s=getchar();
    if(s=='q'||s=='Q')
将s改成字符串却可以，又是什么原因呢？
    printf("\n\tPress \'Q\' to quit!\n");
    scanf("%s",s);
    if(strcmp(s,"q")==0||strcmp(s,"Q")==0)
    .
    .
----------------解决方案--------------------------------------------------------