菜菜鸟..复杂问题 查询删除修改指定数组元素...!

/********************************************************
** Highlight software by yzfy(雨中飞燕) http://yzfy.org *
*********************************************************/
#include <stdio.h>
#include <stdlib.h>

#define N 10

void Menu(void);

int EngineerNo[N],EngineerSex[N],EngineerBirth,EngineerEducation[N],EngineerWorkYears[N],
    yes,year[N],month[N],day[N],i,no;
char EngineerName[N][20],EngineerHometown[N][10],EngineerAddress[N][30],EngineerPhone[N][15],yesno;
float EngineerBaseSalary[N];



void main(void)
{
    while(1)
    {
        int menu=0;

        printf("\t-----------------------------------------------------\n");
        printf("\t|               软件测试工程师管理系统              |\n");
        printf("\t-----------------------------------------------------\n");
        printf("\t1.输入软件测试工程师资料\n");
        printf("\t2.删除指定测试工程师资料\n");
        printf("\t3.查询软件测试工程师资料\n");
        printf("\t4.修改软件测试工程师资料\n");
        printf("\t5.计算测试工程师的月薪水\n");
        printf("\t6.保存新添加的工程师资料\n");
        printf("\t7.对测试工程师信排序(1编号升序,2姓名升序, 3工龄升序)\n");
        printf("\t8.输出所有测试工程师信息\n");
        printf("\t9.清空所有测试工程师数据\n");
        printf("\t10.打印软件测试工程师 数据报表\n");
        printf("\t11.从文件重新导入测试工程师数据\n");
        printf("\t0.结束(编辑工程师信息后提示保存)\n");
        printf("\n\n");
   
   
        printf("\t请输入你的选择:",menu);
        scanf("%d",&menu);
        fflush(stdin);
        {
        switch(menu)
        {
            case    1:
                    Menu();
                    break;

            case     2:
                    /*我就想实现这个！查询指定编号的工程师信息*/
                    break;

            default:
                    printf("\t您输入错误,系统进入主菜单\n");
                    break;
        }
        }
    }
}

/*********工程师输入信息*********/
void Menu(void)
{
    printf("\t确定输入工程师资料？(y/n)");
        while(1)
        {
            scanf("%c",&yesno);
            fflush(stdin);
            
            switch(yesno)    
            {
            case    'y':
                    for (i=0;i<N;i++)
                    {
                    printf("\t请输入工程师编号(1-2000):");
                    EngineerNo[i] = number();
                    fflush(stdin);

                    printf("\t请输入工程师姓名:");
                    scanf("%s",EngineerName[i]);
                    fflush(stdin);

                    printf("\t请输入工程师性别(0为男,1为女):");
                    EngineerSex[i] = engineerSex();
                    fflush(stdin);
                           
                    printf("\t请输入工程师生日(格式1988-06-18):");
                    while(1)
                    {
                    scanf("%d-%d-%d",&year[i],&month[i],&day[i]);
                    yes = engineerBirth(year[i],month[i],day[i]);
                        if (yes==0)
                            break;
                    }
                    fflush(stdin);


                    printf("\t请输入工程师籍贯:");
                    scanf("%s",EngineerHometown[i]);
                    fflush(stdin);

                    printf("\t请输入工程师学历(高中0.学士1.硕士2.博士3.其它为4):");
                    EngineerEducation[i] = engineerEducation();
                    fflush(stdin);

                    printf("\t请输入工程师地址:");
                    scanf("%s",EngineerAddress[i]);
                    fflush(stdin);

                    printf("\t请输入工程师电话:");
                    scanf("%s",EngineerPhone[i]);
                    fflush(stdin);

                    printf("\t请输入工程师工龄(0-50):");
                    EngineerWorkYears[i] = engineerWorkYears(EngineerWorkYears);
                    fflush(stdin);

                    printf("\t请输入工程师基本薪水:");
                    EngineerBaseSalary[i] = engineerBaseSalary();
                    fflush(stdin);

                    printf("\n");
                    printf("\t第%d工程师资料输入完毕,是否输入下一个工程师资料(y/n)?",i+1);
                    scanf("%c",&yesno);
                    fflush(stdin);
                        switch(yesno)    
                        {
                        case    'y':
                                break;
                        case    'n':
                                return;
                        }
                        printf("\n");
                    }        
                    break;

            case    'n':
                    printf("\t返回主菜单\n\n");
                    break;

            default:
                    printf("\t你输入错误请重新输入(y/n):");
            }
            break;
        }
}