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/*下面这个结果是正确的*/ /*你什么编译器*/
#include "stdio.h"#include "conio.h"
#include<math.h>
int main()
{
float amount;
float zijin = 1000.0 ;
float lixi= 0.05 ;
int year ;
printf ("%4s%21s\n","Year", "Amount on deposit") ;
for (year=1; year<=10; year++){
amount = zijin * pow(1.0+lixi, year);
printf ("year=%d amount=%2.2f\n",year, amount );
}
getch();
}
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大哥 你高手哦！
整的乱七八糟！！！
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main()
{
float amount;
float zijin = 1000.0 ;
float lixi= 0.05 ;
int year ;
printf ("%4s%21s\n","Year", "Amount on deposit") ;
for (year=1; year<=10; year++){
zijin = zijin * (1+0.05);
printf ("year=%d amount=%2.2f\n",year, zijin);
}
getch();
}
Year Amount on deposit
year=1 amount=1050.00
year=2 amount=1102.50
year=3 amount=1157.62
year=4 amount=1215.51
year=5 amount=1276.28
year=6 amount=1340.10
year=7 amount=1407.10
year=8 amount=1477.46
year=9 amount=1551.33
year=10 amount=1628.89
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#include "stdio.h"
#include "math.h"
int main()
{
double amount;
double zijin = 1000.0 ;
double lixi= 0.05 ;
int year ;
printf ("%4s%21s\n","Year", "Amount on deposit") ;
for (year=1; year<=10; year++)
{
amount = zijin * pow(1.0+lixi, year);
printf ("%4d%17.2f\n",year, amount );
}
getch();
}
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#include "stdio.h"
#include "conio.h"
#include<math.h>
int main()
{
double amount;
double zijin = 1000.0;
double lixi= 0.05;
int year;
printf ("%4s%21s\n","Year","Amount on deposit");
for (year=1;year<=10;year++){
amount = zijin*pow(1.0+lixi,year);
printf ("%4f%21.2f\n",year,amount );
}
getch();
}
这个是运行结果,说乱七八糟是指的结果比较乱,而不是程序有问题,呵呵,
[[italic] 本帖最后由 devil_v6 于 2008-1-25 10:52 编辑 [/italic]]
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上面的程序用的是xianshizhe111大哥的程序
应该是在输出结果的时候将小数点后的位数控制一下就可以了
用15楼的方法printf ("%4d%17.2f\n",year, amount );
结果如下:
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