;将a段与b段数据依次相加，结果依次放进c段
assume cs:code
a segment
db 1,2,3,4,5,6,7,8
a ends
b segment
db 1,2,3,4,5,6,7,8
b ends
c segment
db 0,0,0,0,0,0,0,0
c ends
code segment
start:
mov ax,a
mov ds,ax
mov bx,0
mov cx,8
s:
mov al,[bx]
add al,[bx+16]
mov ds:[bx+32],al
inc bx
loop s
mov ax,4c00h
int 21h
code ends
end start
请帮我看看呢？
------解决思路----------------------
每一个段是16bytes,就算你一个段只放一个bytes
编译器仍会补足一个段
内存,看起来会是
1,2,3,4,5,6,7,8,0,0,0,0,0,0,0,
1,2,3,4,5,6,7,8,0,0,0,0,0,0,0,
所是+16