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android 发送一个http请求的有关问题

热度:53   发布时间:2016-04-28 03:17:01.0
android 发送一个http请求的问题

我是个新手,目前想在android app中发起一个简单的http请求,该请求到一个php页面左的网页上取一些数据,有没有可以通过后台运行去网站取数据并解析的功能?

第一步,把下面的代码加入到你的 manifest 文件中,目的是放开网络访问权限
<uses-permission android:name="android.permission.INTERNET" />

然后就可以使用 Apache http client 访问页面了,在android中非常的简单就能完成

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HttpClient httpclient = newDefaultHttpClient();
    HttpResponse response = httpclient.execute(newHttpGet(URL));
    StatusLine statusLine = response.getStatusLine();
    if(statusLine.getStatusCode() == HttpStatus.SC_OK){
        ByteArrayOutputStream out = newByteArrayOutputStream();
        response.getEntity().writeTo(out);
        out.close();
        String responseString = out.toString();
        //..more logic
    }else{
        //Closes the connection.
        response.getEntity().getContent().close();
        thrownew IOException(statusLine.getReasonPhrase());
    }

如果你想在后台访问或者异步的方式运行,需要继承 AsyncTask,AsyncTask是专门单独线程跑后台任务的类

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classRequestTask extendsAsyncTask<string, string=""string,="">{
 
    @Override
    protectedString doInBackground(String... uri) {
        HttpClient httpclient = newDefaultHttpClient();
        HttpResponse response;
        String responseString = null;
        try{
            response = httpclient.execute(newHttpGet(uri[0]));
            StatusLine statusLine = response.getStatusLine();
            if(statusLine.getStatusCode() == HttpStatus.SC_OK){
                ByteArrayOutputStream out = newByteArrayOutputStream();
                response.getEntity().writeTo(out);
                out.close();
                responseString = out.toString();
            }else{
                //Closes the connection.
                response.getEntity().getContent().close();
                thrownew IOException(statusLine.getReasonPhrase());
            }
        }catch(ClientProtocolException e) {
            //TODO Handle problems..
        }catch(IOException e) {
            //TODO Handle problems..
        }
        returnresponseString;
    }
 
    @Override
    protectedvoid onPostExecute(String result) {
        super.onPostExecute(result);
        //Do anything with response..
    }
}</string,>

最后你可以通过如下的方式调用

new RequestTask().execute("http://stackoverflow.com");


原文地址:http://www.itmmd.com/201410/91.html

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