关于jquery接不到值的缘故

<script type="text/javascript">
    $(document).ready(function () {

        $("p").click(function () {
            $.post("ashx/test.ashx", function (data, status) {
                var comments = $.parseJSON(data);
                for (var i = 0; i < comments.length; i++) {
                    var comment = comments[i];
                    var book = $("<p>正题名:" + comment.ztm + "</p><br/><p>内容简介:" + comment.nrjj + "</p>");
                    $("#k").append(book);
                }

            });
        });


    })
  
</script>

 public void ProcessRequest(HttpContext context)
        {
            context.Response.ContentType = "text/html";
            BookTest bt = new BookTest();
            List<BookTest> list = new List<BookTest>();
            bt.Nrjj = "发改委成立至今只做过两件事：1、涨价，2、替涨价辩护.";
            bt.Ztm = "中国";
            list.Add(bt);
            JavaScriptSerializer jss = new JavaScriptSerializer();
            string data = jss.Serialize(list);
            context.Response.Write(data);
        }
        public bool IsReusable
        {
            get
            {
                return false;
            }
        }