xml节点有关问题 _XML/SOAP

xml节点问题

XML code


<?xml version="1.0"?>
<root>
    <status>ok</status>
    <body><root><prozl>1</prozl><prol><div><a href="/webcn/UploadFiles/Shop/201001201456080338.jpg" target="_blank" class="highslide" onclick="return hs.expand(this)"><img src="/webcn/UploadFiles/Shop/201001201456080338.jpg" border="0" onerror="this.src='/webcn/UploadFiles/nopic.gif'" /></a><div class="highslide-heading">7CF钛金尊品离子蜡</div></div><div class="newP_Info"><a href="/webcn/Item/945.aspx" target="_blank">7CF钛金尊品离子蜡</a><br />
价格：
<strong>
￥230.40×1</strong></div></prol></root></body>
    <pagename/>
    <total>1</total>
    <currentpage>1</currentpage>
    <pagesize>0</pagesize>
</root>

要取prozl和prol的值怎么办？
var objxml = createDomDoc();
objxml.loadXML(xmlcon)

document.getElementById("dg").innerHTML=objxml.selectNodes("/root/body/root/prozl")[0].firstChild.nodeValue;
这个可以取到

document.getElementById("NewShopping").innerHTML=objxml.selectNodes("/root/body/root/prol")[0].firstChild.nodeValue;
这个是null

------解决方案--------------------

JScript code

function load(url){
  var dom=false;
  if(document.all)dom=new ActiveXObject("microsoft.xmldom");
  else if(document.implementation&&document.implementation.createDocument)dom=document.implementation.createDocument("","",null);
  dom.async=false;
  dom.load(url);
  return dom;
}
var dom=load("x.xml"),prol=dom.getElementsByTagName('prol'),prozl=dom.getElementsByTagName('prozl');
alert(prozl[0].firstChild.nodeValue)//prozl

var tmp=document.all?prol[0].xml:new XMLSerializer().serializeToString(prol[0]);
tmp=tmp.replace('<prol>','').replace('</prol>','');//替换掉首尾节点字符串
alert(tmp)