1. 在Eclipse中建立Maven工程
1.1 新建Maven工程
1.2 选择默认工作空间
1.3 选择 maven-archetype-webapp Archetype
1.4 填写Group id,Artifact id,package
1.5 生成的web工程初始目录结构
2. 添加工程依赖
2.1 用Maven POM Editor 打开pom.xml文件,在Dependencies中添加依赖包
2.2 在查询栏中输入“resteasy-jaxrs”,在查询结果中选择版本3.0.0
2.3 保存pom.xml后,manvn从中央代码仓库自动下载依赖包
3. REST Service
package com.example.rest.resteasy.service; import javax.ws.rs.GET; import javax.ws.rs.Path; import javax.ws.rs.PathParam; import javax.ws.rs.core.Response; @Path("/hello") public class HelloWorldRestService { @GET @Path("/{param}") public Response getName(@PathParam("param") String name) { String result = "RESTEasy Hello World : " + name; return Response.status(200).entity(result).build(); } }
4. Rest Application
package com.example.rest.resteasy.app; import java.util.HashSet; import java.util.Set; import javax.ws.rs.core.Application; import com.example.rest.resteasy.service.HelloWorldRestService; public class HelloWorldApplication extends Application { private Set<Object> singletons = new HashSet<Object>(); public HelloWorldApplication() { singletons.add(new HelloWorldRestService()); } @Override public Set<Object> getSingletons() { return singletons; } }
5. web.xml
<!DOCTYPE web-app PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN" "http://java.sun.com/dtd/web-app_2_3.dtd" > <web-app> <display-name>Archetype Created Web Application</display-name> <servlet> <servlet-name>resteasy-servlet</servlet-name> <servlet-class> org.jboss.resteasy.plugins.server.servlet.HttpServletDispatcher </servlet-class> <init-param> <param-name>javax.ws.rs.Application</param-name> <param-value>com.example.rest.resteasy.app.HelloWorldApplication</param-value> </init-param> </servlet> <servlet-mapping> <servlet-name>resteasy-servlet</servlet-name> <url-pattern>/*</url-pattern> </servlet-mapping> </web-app>
6. Run AS -> run jetty
在这个例子中,web请求“http://localhost:8080/resteasy-example/hello”将匹配HelloWorldRestService,“http://localhost:8080/resteasy-example/hello/{任意值}”将匹配到方法参数@PathParam 参数