例如某表
Name FuckDate MMName FuckPlace
-----------------------------------
LZ 2007-03-08 Lily Home
LZ 2007-03-09 Lily Hotel
LZ 2007-03-15 Lisa Home
LZ 2007-03-20 Lily Car
LZ 2007-03-21 Lily Street
要求输入LZ，得到Lily
怎么实现呢？
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select top 1 MMName
from tablename
where name = 'LZ '
group by MMName
order by count(1) desc
------解决方案--------------------
select top 1 MMName from 表
where NAME= 'LZ '
group by MMName ordey by count(MMName) desc
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晕,楼上的仔细
我还没看出来呢
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果然是
------解决方案--------------------
Name FuckDate MMName FuckPlace
-----------------------------------
LZ 2007-03-08 Lily Home
LZ 2007-03-09 Lily Hotel
LZ 2007-03-15 Lisa Home
LZ 2007-03-20 Lily Car
LZ 2007-03-21 Lily Street
－－－－－－－－－－－－－－－－－－
弓虽！
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作 者： chieftech (纯真处男，欢迎诱奸（QJ太疼）)
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查询的结果是最佳女主角？三八红旗手？
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select top 1 'LZ like '+mmname+ ' best.often in '+fuckplace from 表
where name= 'lz '
group by all mmname,fuckplace
order by count(*) desc
楼主猜结果是什么?
------解决方案--------------------
to：gahade，凡事就怕认真……
--创建测试环境
create table 表(Name varchar(10),FuckDate datetime,MMName varchar(10),FuckPlace varchar(10))
--插入测试数据
insert 表(Name,FuckDate,MMName,FuckPlace)
select 'LZ ', '2007-03-08 ', 'Lily ', 'Home ' union all
select 'LZ ', '2007-03-09 ', 'Lily ', 'Hotel ' union all
select 'LZ ', '2007-03-15 ', 'Lisa ', 'Home ' union all
select 'LZ ', '2007-03-20 ', 'Lily ', 'Car ' union all
select 'LZ ', '2007-03-21 ', 'Lily ', 'Street '
--求解过程
select top 1 'LZ like '+mmname+ ' best.often in '+fuckplace from 表
where name= 'lz '
group by all mmname,fuckplace
order by count(*) desc
--删除测试环境
drop table 表
/*--测试结果
-------------------------------------------
LZ like Lily best.often in Home
（所影响的行数为 1 行）
*/