public int ID(decimal jingdu,decimal weidu)
{
int i = 0;
string strconn = "Data Source=ANDY;Initial Catalog=GUIDE;Integrated Security=True ";
SqlConnection conn = new SqlConnection(strconn);
SqlCommand comm = new SqlCommand( " ", conn);
comm.CommandText = "select ID from andy where square([email protected])+square([email protected])=(select min(([email protected])+square([email protected])) from andy) ";
comm.Parameters.Add( "jing ",SqlDbType.Decimal);
comm.Parameters.Add( "wei ", SqlDbType.Decimal);
comm.Parameters[ "jing "].Value = jingdu;
comm.Parameters[ "wei "].Value = weidu;
conn.Open();
SqlDataReader result = comm.ExecuteReader();
if (result.Read() ==true)
{
i = (int)result[0];
}
conn.Close();
return i;
}
我的目的是接收到一个经纬度信息之后,与数据库里的经纬度信息比较后,返回与接收经纬度最接近的经纬度的ID号,可是运行之后,只能接收与数据库里相同的经纬度信息,如果接收到的信息数据库里不存在,就会返回初始值0,这是为什么??
------解决方案--------------------
你的SQL語句是用相等作判斷條件的,當然不可能返回最接近的值
------解决方案--------------------
select ID from andy a where not exists (select * from andy b where square([email protected]) + square([email protected]) < ([email protected]) + square([email protected])) and a.longitude <> @jing and a.latitude <> @wei
用这个吧.
id可能返回多个,举个简单的,如果有2个点相对 (@jing,@wei)对称的话.