比如
@name是变量,字段name需要模糊匹配
select * from person where name like
后面怎么写呢?
谢了
------解决方案--------------------
select * from person where name like '% '[email protected]+ '% '
------解决方案--------------------
exec( 'select * from person where name like ' '% '[email protected]+ '% ' ' ')
------解决方案--------------------
select * from person where name like '% '[email protected]+ '% '
------解决方案--------------------
declare @str nvarchar(40)
set @str= 'zh '
select * from a where fmemo like '% '[email protected]+ '% '
------解决方案--------------------
CREATE PROC PS_TEST
@NAME NVARCHAR(20)
AS
BEGIN
SET NOCOUNT ON
SELECT * FROM person WHERE [name] LIKE '% '[email protected]+ '% '
SET NOCOUNT OFF
END
GO
EXEC PS_TEST '义 '
DROP PROC PS_TEST
------解决方案--------------------
select * from person where name like '%[ '[email protected]+ ']% '
------解决方案--------------------
declare @name char(10)
set @name= '123 '
print( 'select * from person where name like ' '% '+ltrim(rtrim(@name))+ '% ' ')
先把得到的语句print出来
------解决方案--------------------
@AppName char(20)=null,
改為
@AppName varchar(20)=null,