当前位置: 代码迷 >> Sql Server >> 100分求条sql语句.吃完饭来有结果马上结贴解决办法
  详细解决方案

100分求条sql语句.吃完饭来有结果马上结贴解决办法

热度:32   发布时间:2016-04-27 15:16:03.0
100分求条sql语句....吃完饭来有结果马上结贴
SQL code
--字段:ID    Year    TypeID1        TypeID2        Title    UpdateTime--说明:TpyeID2在TypeID1下 如:TypeID1=1:的时候TypeID2有三个值:1、2、3--查询结果:根据这两个类别去分别查询出5条数据然后根据Year,UpdateTime倒序。注意是根据类别分别查询出5条数据。如果TypeID1的值为1或者2。TypeID2为1、2、3--那么全部的数据就为30条了。5条*6=30

谁第一个回答出100分全给哪位

------解决方案--------------------
SQL code
--------------------------------- 
--  Author: liangCK 小梁
--  Title : 查每个分组前N条记录
--  Date  : 2008-11-13 17:19:23
---------------------------------

--> 生成测试数据: #T
IF OBJECT_ID('tempdb.dbo.#T') IS NOT NULL DROP TABLE #T
CREATE TABLE #T (ID VARCHAR(3),GID INT,Author VARCHAR(29),Title VARCHAR(39),Date DATETIME)
INSERT INTO #T
SELECT '001',1,'邹建','深入浅出SQLServer2005开发管理与应用实例','2008-05-10' UNION ALL
SELECT '002',1,'胡百敬','SQLServer2005性能调校','2008-03-22' UNION ALL
SELECT '003',1,'格罗夫Groff.J.R.','SQL完全手册','2009-07-01' UNION ALL
SELECT '004',1,'KalenDelaney','SQLServer2005技术内幕存储引擎','2008-08-01' UNION ALL
SELECT '005',2,'Alex.Kriegel.Boris.M.Trukhnov','SQL宝典','2007-10-05' UNION ALL
SELECT '006',2,'飞思科技产品研发中心','SQLServer2000高级管理与开发','2007-09-10' UNION ALL
SELECT '007',2,'胡百敬','SQLServer2005数据库开发详解','2008-06-15' UNION ALL
SELECT '008',3,'陈浩奎','SQLServer2000存储过程与XML编程','2005-09-01' UNION ALL
SELECT '009',3,'赵松涛','SQLServer2005系统管理实录','2008-10-01' UNION ALL
SELECT '010',3,'黄占涛','SQL技术手册','2006-01-01'

--SQL查询如下:

--按GID分组,查每个分组中Date最新的前2条记录


--1.字段ID唯一时:
SELECT * FROM #T AS T WHERE ID IN(SELECT TOP 2 ID FROM #T WHERE GID=T.GID ORDER BY Date DESC)

--2.如果ID不唯一时:
SELECT * FROM #T AS T WHERE 2>(SELECT COUNT(*) FROM #T WHERE GID=T.GID AND Date>T.Date)

--SQL Server 2005 使用新方法

--3.使用ROW_NUMBER()进行排位分组
SELECT ID,GID,Author,Title,Date
FROM
(
SELECT rid=ROW_NUMBER() OVER(PARTITION BY GID ORDER BY Date DESC),*
FROM #T
) AS T
WHERE rid <=2

--4.使用APPLY
SELECT DISTINCT b.*
FROM #T AS a
CROSS APPLY
(
  SELECT TOP(2) * FROM #T WHERE a.GID=GID ORDER BY Date DESC
) AS b


--结果
/*

ID  GID    Author            Title                  Date
---- ----------- ----------------------------- --------------------------------------- -----------------------
003  1      格罗夫Groff.J.R.        SQL完全手册                2009-07-01 00:00:00.000
004  1      KalenDelaney          SQLServer2005技术内幕存储引擎          2008-08-01 00:00:00.000
005  2      Alex.Kriegel.Boris.M.Trukhnov SQL宝典                  2007-10-05 00:00:00.000
007  2      胡百敬              SQLServer2005数据库开发详解          2008-06-15 00:00:00.000
009  3      赵松涛              SQLServer2005系统管理实录          2008-10-01 00:00:00.000
010  3      黄占涛              SQL技术手册                2006-01-01 00:00:00.000

(6 行受影响)
*/


--得到每组前几条数据
--假設每組Col1中, Col3不會重復

--建立測試環境
Create Table TEST
(Col1 Varchar(10),
Col2 Varchar(10),
Col3 Int)
--插入數據
Insert TEST Select 'BD1V','Label', 4
Union All Select 'BD1V', 'BATT', 2
Union All Select 'BD1V', 'ODD', 3
Union All Select 'BD1V', 'HDD', 5
Union All Select 'BD1V', 'LCD', 1
Union All Select 'BD1W','HDD', 3
Union All Select 'BD1W','RAM', 8
Union All Select 'BD1W','TP CABLE', 5
Union All Select 'BD1W','LCD', 6
Union All Select 'BD1W','Label', 2
Union All Select 'BL3', 'LCD CABLE', 7
Union All Select 'BL3', 'LABEL', 6
Union All Select 'BL3', 'LCD', 5
Union All Select 'BL3', 'RAM', 1
Union All Select 'BL3D', 'Label', 4
GO
--測試
--方法一:
Select Col1, Col2, Col3 From TEST A
Where (Select Count(*) From TEST Where Col1 = A.Col1 And Col3 > A.Col3) < 3
Order By Col1, Col3 Desc
--方法二:
Select Col1, Col2, Col3 From TEST A
Where Exists (Select Count(*) From TEST Where Col1 = A.Col1 And Col3 > A.Col3 Having Count(*) < 3)
Order By Col1, Col3 Desc
--方法三:
Select Col1, Col2, Col3 From TEST A
Where Col3 In (Select TOP 3 Col3 From TEST Where Col1 = A.Col1 Order By Col3 Desc)
Order By Col1, Col3 Desc
GO
--刪除測試環境
Drop Table TEST
--結果
/*
Col1  Col2  Col3
BD1V HDD  5
BD1V Label  4
BD1V ODD  3
BD1W RAM  8
BD1W LCD  6
BD1W TP CABLE 5
BL3  LCD CABLE 7
BL3  LABEL  6
BL3  LCD  5
BL3D Label  4
*/

------解决方案--------------------
SQL code
SELECT   *FROM(   SELECT rid=ROW_NUMBER() OVER(PARTITION BY TypeID1,TypeID2 order by [Year],UpdateTime desc),*   FROM tb) AS TWHERE rid<=5
  相关解决方案