- SQL code
set ANSI_NULLS ONset QUOTED_IDENTIFIER ONgo ALTER FUNCTION [dbo].[fnGetDistance] --LatBegin 开始经度 --LngBegin 开始维度(@LatBegin REAL, @LngBegin REAL, @LatEnd REAL, @LngEnd REAL) RETURNS FLOAT ASBEGIN --距离(千米) DECLARE @Distance REAL DECLARE @EARTH_RADIUS REAL SET @EARTH_RADIUS = 6378.137 DECLARE @RadLatBegin REAL, @RadLatEnd REAL, @RadLatDiff REAL, @RadLngDiff REAL SET @RadLatBegin = @LatBegin *PI()/ 180.0 SET @RadLatEnd = @LatEnd *PI()/ 180.0 SET @RadLatDiff = @RadLatBegin - @RadLatEnd SET @RadLngDiff = @LngBegin *PI()/ 180.0 - @LngEnd *PI()/ 180.0 SET @Distance = 2 *ASIN( SQRT( POWER(SIN(@RadLatDiff / 2), 2)+COS(@RadLatBegin)*COS(@RadLatEnd) *POWER(SIN(@RadLngDiff / 2), 2) ) ) SET @Distance = @Distance * @EARTH_RADIUS --SET @Distance = Round(@Distance * 10000) / 10000 RETURN @DistanceEND
要怎么修改才能Select dbo.fnGetDistance
('119.959416','30.273575',(select hotel_mapx from hotelinfo),(select hotel_mapx from hotelinfo))
------解决方案--------------------
declare @a type
select @a=(select top 1 hotel_mapx from hotelinfo)
Select dbo.fnGetDistance('119.959416','30.273575',@a,@a)