1.查录30-40条记录,根据ID不连续的排序查询。
2.有一个新闻表和目录表,查询每个目录下最新的一条新闻。
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select * from (select row_number() over(order by id) num,* from table) t
where t.num between 30 and 40
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1.查录30-40条记录,根据ID不连续的排序查询。
select top 11 * from (select top 40 * from tb order by id) t order by id desc
--其他内容见下:
- SQL code
取n到m条记录的语句1.select top m * from tablename where id not in (select top n id from tablename)2.select top m * into 临时表(或表变量) from tablename order by columnname -- 将top m笔插入set rowcount nselect * from 表变量 order by columnname desc3.select top n * from (select top m * from tablename order by columnname) aorder by columnname desc4.如果tablename里没有其他identity列,那么:select identity(int) id0,* into #temp from tablename取n到m条的语句为:select * from #temp where id0 >=n and id0 <= m如果你在执行select identity(int) id0,* into #temp from tablename这条语句的时候报错,那是因为你的DB中间的select into/bulkcopy属性没有打开要先执行:exec sp_dboption 你的DB名字,'select into/bulkcopy',true5.如果表里有identity属性,那么简单:select * from tablename where identitycol between n and m 6.如果是sql server 2005 可以这样写: select top 20 * from T order by colexceptselect top 2 * from T order by col
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- SQL code
1. select top 10 * from a where id not in (select top 30 * from a)2. 新闻表 news 目录表 mulu select top 1 a.*,b.muluname from news as a,mulu as b where a.muliid=b.id group by a.muliid order by a.time desc
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select top 11 * from (select top 40 * from tb order by id) t order by id desc
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学习,留下点\\\
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所谓ID不连续,就比如;
id
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那为什么题目上要明确指出id不连续呢,因为如果id是连续的,我们就可以有
select * from table where id between 30 and 40
这样的查询方式
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select top 10 * from a where id not in (select top 29 * from a)