有这样一张表
- SQL code
create table DBTest (OID int,Oname nvarchar(100),PID int,Com nvarchar(100))insert into DBTest values ('12345','ABC','364','CZZXXCC')insert into DBTest values ('12346','ABC','364','EZZXXEE')insert into DBTest values ('12350','DFGFG','362','CCZZXXDD')insert into DBTest values ('12351','DFGFG','365','EEZZXXFF')insert into DBTest values ('12355','XXCVD','362','WWZZXXD')insert into DBTest values ('12356','XXCVD','364','GGZZXXV')
如何Oname一样,但PID不一样的OID来。
------解决方案--------------------
- SQL code
SELECT a.* FROM dbtest a INNER JOIN dbtest b ON a.oname=b.onameWHERE a.pid<>b.pid/*OID Oname PID Com----------- ---------------------------------------------------------------- ----------- ----------------------------------------------------------------12351 DFGFG 365 EEZZXXFF12350 DFGFG 362 CCZZXXDD12356 XXCVD 364 GGZZXXV12355 XXCVD 362 WWZZXXD(4 行受影响)*/