SQL话语合并，求帮忙

SQL语句合并，求帮忙
select count(*) as jysum 
from Member, Card ,Trading 
where Member.ID=Card.UserID and Card.State<>'3' and (Member.ID=Trading.buyID or Member.ID=Trading.sellID )
group by Member.ID


select distinct Member.ID,Member.Acc,Member.Peoplename,Member.Mobile,Card.State
from Member, Card ,Trading
where Member.ID=Card.UserID and Card.State<>'3' and (Member.ID=Trading.buyID or Member.ID=Trading.sellID ) 

第一段查的结果为
jysum
A条
B条
C条
第二段的结果为
.ID .Acc .Peoplename .Mobile .State
1 XX XX XX XX
2 XX XX XX XX
3 XX XX XX XX
我想对上面2段SQL语句进行合并，合并的效果为
.ID .Acc .Peoplename .Mobile .State jysum 
1 XX XX XX XX A条
2 XX XX XX XX B条
3 XX XX XX XX C条

意思是，ID为1的出现了A条（比如5条）ID为2的出现了B条（比如3）

原始
select Member.ID,Member.Acc,Member.Peoplename,Member.Mobile,Card.State
from Member, Card ,Trading
where Member.ID=Card.UserID and Card.State<>'3' and (Member.ID=Trading.buyID or Member.ID=Trading.sellID ) 
效果为
.ID .Acc .Peoplename .Mobile .State
1 XX XX XX XX
1 XX XX XX XX
1 XX XX XX XX
1 XX XX XX XX
1 XX XX XX XX
2 XX XX XX XX
2 XX XX XX XX
2 XX XX XX XX

------解决方案--------------------

SQL code

SELECT  Member.ID ,        Member.Acc ,        Member.Peoplename ,        Member.Mobile ,        Card.STATE ,        COUNT(1) AS jysumFROM    Member ,        Card ,        TradingWHERE   Member.ID = Card.UserID        AND Card.State <> '3'        AND ( Member.ID = Trading.buyID              OR Member.ID = Trading.sellID            )GROUP BY Member.ID ,        Member.Acc ,        Member.Peoplename ,        Member.Mobile ,        Card.STATE