我想做一个键盘，键盘上有二者显示的内容
我的想法是通过一个控件的的鼠标信号来改变第一级Item的一个属性，在由这个属性来修改每个控件的显示内容。
- CSS code
Item { id: softkey width: 800 height: 388 clip: false property bool m_shift: false; Rectangle { id: rectangle1 x: 0 y: 0 width: 800 height: 388 Key { id: key1 x: 10 y: 163 width: 84 height: 50 key_name1 : " " key_name2 : " " MouseArea { onReleased : softkey.m_shift = !softkey.m_shift; } } }- C/C++ code
Item { id: key width: 100 height: 62 property string key_name1; property string key_name2; Rectangle { id: rectangle1 Text { id: text1; text: key_name1 } } MouseArea { id: mouse_area1 anchors.fill: parent } states: [ State { name: "state2";when: solftkey.m_shift PropertyChanges { target: text1 text: key_name2 } } ]}但我这样做根本不下，哪位大仙指导一下，已经2天了
------解决方案--------------------
// import QtQuick 1.0 // to target S60 5th Edition or Maemo 5
import QtQuick 1.1
Item {
id: key
width: 100
height: 62
property string key_name1;
property string key_name2;
state:"state1"
Rectangle {
id: rectangle1
width: 100
height: 62
color: "lightblue"
Text {
id: text1;
text: key_name2
}
}
states: [
State {
name: "state2";when: solftkey.m_shift
PropertyChanges {
target: text1
text: key_name2
}
},
//!!!!!!!!!!!!!!!!!!!!!!!!!!
State {
name: "state1";when: solftkey.m_shift
PropertyChanges {
target: text1
text: key_name1
}
}
//!!!!!!!!!!!!!!!!!!!!!!!!!!
]
}
// import QtQuick 1.0 // to target S60 5th Edition or Maemo 5
import QtQuick 1.1
Item {
id: softkey
width: 800
height: 388
clip: false
property bool m_shift: false;
Rectangle {
id: rectangle1
x: 0
y: 0
width: 800
height: 388
Key {
id: key1
x: 10
y: 163
width: 84
height: 50
key_name1 : "key_name1"//!!!!!!!!!!!!!!!!!!!!!!!!!!
key_name2 : "key_name2"//!!!!!!!!!!!!!!!!!!!!!!!!!!
MouseArea {
anchors.fill: parent//!!!!!!!!!!!!!!!!!!!!!!!!!!
onReleased :
{
key1.state = (key1.state==="state1"? "state2":"state1")//!!!!!!!!!!!!!!!!!!!!!!!!!!
softkey.m_shift = !softkey.m_shift;//!!!!!!!!!!!!!!!!!!!!!!!!!!
console.log(key1.state)
}
}
}
}
}
冒昧的修改了下楼主的代码（已用！！！！标出），不知道楼主要的是不是这种效果。